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CaHeK987 [17]
1 year ago
15

I need the right answer!thanks in advance^^ ​

Mathematics
1 answer:
LiRa [457]1 year ago
3 0

The questions are illustrations of combination and permutation.

<h3>The different arrangement of LOVE</h3>

From the question, we understand that the letter V must come first.

So, we have:

  • First letter = 1; i.e. V
  • The second letter can be any of the remaining 3
  • The third letter can be any of the remaining 2
  • The last letter can be the remaining 1

So, we have:

Arrangement = 1 * 3 * 2 * 1

Arrangement = 6

Hence, there are 6 different arrangement of the letters.

<h3>Ways to pick two vegetables</h3>

We have:

  • Vegetables, n = 5
  • To pick, r = 2

The number of different combination is:

Combination = ^5C_2

Evaluate

Combination = 10

Hence, there are 10 different ways

<h3>Number of 4-digit code</h3>

The numbers are given as {1,4,5,7,8}

So, we have:

  • The first digit can be any of the 5 digits
  • The second digit can be any of the remaining 4 digits
  • The third digit can be any of the remaining 3 digits
  • The fourth digit can be any of the remaining 2 digits

So, we have:

Digits = 5 * 4 * 3 * 2

Digits = 120

Hence, there are 120 different codes of 4-digit

<h3>Arrangement of books in a shelf</h3>

We have:

  • Books, n = 4

The number of arrangement is:

Arrangement = 4!

Evaluate

Arrangement = 24

Hence, there are 24 different arrangements

<h3>Outcomes in tossing a coin</h3>

A coin has 2 faces

When four coins are tossed, the number of outcomes is:

Outcome = 2 * 2 * 2* 2

Evaluate

Outcome = 16

Hence, there are 16 different outcomes

<h3>Ways of sitting in a row</h3>

The number of people is given as:

People = 5

So, we have:

  • The first person can sit on any of the 5 seats
  • The second person can sit on any of the 4 seats
  • The third person can sit on any of the 3 seats
  • The fourth person can sit on any of the 2 seats
  • The last person would sit on the remaining seat1

So, we have:

Ways = 5 * 4 * 3 * 2 * 1

Ways = 120

Hence, there are 120 different ways

Read more about combination and permutation at:

brainly.com/question/11732255

#SPJ1

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