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3 years ago

Can someone help me with this problem (-3x+15) + (-3x + 2)

Mathematics

2 answers:

8_murik_8 [283]3 years ago

3 0

=-3x +15 -3x + 2
= 15 +2
= 17

pychu [463]3 years ago

3 0

Other ones wrong.
-3x+-3x=-6x
15+2=17

-6x+17

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Write an equation for an ellipse centered at the origin, which has foci at (\pm8,0)(±8,0)left parenthesis, plus minus, 8, comma,

mario62 [17]

Answer:

The equation of the ellipse is $\frac{x^{2}}{(17)^{2}}+\frac{y^{2}}{(15)^{2}}=1$

Step-by-step explanation:

The standard form of the equation of an ellipse with center (0 , 0) is

$\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1$ , where

The coordinates of the vertices are (± a , 0)

The coordinates of the foci are (± c , 0) , where c ² = a² - b²

∵ The ellipse is centered at the origin

∴ The center of it is (0 , 0)

∵ It has foci at (± 8 , 0)

- The coordinates of the foci are (± c , 0)

∴ c = ±8

∵ It has Vertices at (± 17 , 0)

- The coordinates of the vertices are (± a , 0)

∴ a = ±17

∵ c² = a² - b²

- Substitute the values of c and a to find b

∴ (8)² = (17)² - b²

∴ 64 = 289 - b²

- Add b² to both sides

∴ b² + 64 = 289

- Subtract 64 from both sides

∴ b² = 225

- Take √ for both sides

∴ b = ± 15

∵ The equation of the ellipse is $\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1$

- Substitute the values of a and b in it

∴ $\frac{x^{2}}{(17)^{2}}+\frac{y^{2}}{(15)^{2}}=1$ ⇒ $\frac{x^{2}}{289}+\frac{y^{2}}{225}=1$

∴ The equation of the ellipse is $\frac{x^{2}}{(17)^{2}}+\frac{y^{2}}{(15)^{2}}=1$

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3 years ago

Sandra used partial products to find the product of 438 × 17 by multiplying 438 by 1 and 438 by 7 to get 3,066. Find the product

boyakko [2]

Let us determine the product of 438 and 17 by partial products.

Consider $438 = 400+30+8$

and $17 = 10+7$

So, $438 \times 17 = (400+30+8) \times (10+7)$

$438 \times 17 = (400\times 10)+(30 \times 10)+(8 \times 10) +(400 \times 7)+(30 \times 7)+(8 \times 7)$

= $438 \times 17 = (4000+300+80+2800+210+56)$

= 7446

Therefore, the product of 438 and 17 is 7446.

No, Sandra's answer is not correct.

Because she should have expressed 17 as (10+7), then if she multiplied (438 by 10) and (438 by 7). And, then added the results.Then her answer would be correct.

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