Let's assume
the price of each train ticket is x
we are given
total number of family members =5
so, total cost of ticket = total number of family members*the price of each ticket
so, total cost of ticket =5*x
so, total cost of ticket =5x
now, we have
each family member buys a boxed lunch for $6.50
so, total cost of lunch box = total number of family members*price of each lunch box
so, total cost of lunch box = 5*6.50
total cost of trip = total cost of ticket+total cost of lunch box
we are given
total cost of trip is $248.50
now, we can plug values
and we get
![248.50=5x+5*6.50](https://tex.z-dn.net/?f=%20248.50%3D5x%2B5%2A6.50%20)
now, we can solve for x
![248.50=5x+32.5](https://tex.z-dn.net/?f=%20248.50%3D5x%2B32.5%20)
![248.50-32.5=5x+32.5-32.5](https://tex.z-dn.net/?f=%20248.50-32.5%3D5x%2B32.5-32.5%20)
![216=5x](https://tex.z-dn.net/?f=%20216%3D5x%20)
![\frac{5x}{5} =\frac{216}{5}](https://tex.z-dn.net/?f=%20%5Cfrac%7B5x%7D%7B5%7D%20%3D%5Cfrac%7B216%7D%7B5%7D%20%20)
![x=43.2](https://tex.z-dn.net/?f=%20x%3D43.2%20)
so,
the price of each train ticket is $43.2..........Answer