Hi there! Okay well to find out the width when you all ready have the perimeter and length just add up both sides of the length, 55+55=110 okay now just subtract 110 from 154, 154-110=44 now since there are to sides for width in a rectangle divide 44 by 2, 44÷2=22 so your width is 22 now to check add up all your side's: 55+22+55+22=154 ANSWER: width = 22ft
<span>The expression of the square root of 19x must be simplified when x is equal to 28. This is because possible factors of 28 can be seen to be 4 and 7, and 4 is a perfect square. This means it can be pulled outside of the square root when evaluated. The other options include only prime factors that could not be pulled out. (3,5), (3,7), (1,41)
28 simplifies as such:
Sqrt(19*28) = Sqrt(19*4*7) = 2*Sqrt(19*7) = 2*Sqrt(133).</span>
Answer:
m∠KIJ = m∠LIM ⇒ answer B
Step-by-step explanation:
* Lets explain how to solve the problem
∵ I is the mid-point of NH
∴ IN = IH
- MJ is perpendicular to NH and passes through I the mid-point of NH
∴ MJ is perpendicular bisector of NH
- NH ⊥ MJ and intersects it at I
∴ m∠NIM = m∠NIJ = 90°
- ∠ NIM consists of two angles ∠NIL and ∠MIL
∵ m∠NIM = m∠NIL + m∠MIL
- ∠NIJ consists of two angles ∠NIK and ∠JIK
∵ m∠NIJ = m∠NIK + m∠JIK
∴ m∠NIL + m∠MIL = m∠NIK + m∠JIK ⇒ (1)
∵ NH bisects ∠KIL
∴ m∠NIL = m∠NIK ⇒ (2)
- From (1) and (2)
∴ m∠MIL = m∠JIK
* m∠KIJ = m∠LIM
Answer:
The diameter of the target is 
Step-by-step explanation:
we know that
In this problem the distance from the center of an archery target to the outside edge of the target is equal to the radius of the target
so
Remember that
The diameter is two times the radius
substitute
sorry ill give points back
it's this tally/nathan?
