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solmaris [256]
3 years ago
14

Kira has 10 socks in a drawer. There are 6 white socks, 2 black socks, and 2 striped socks. Without looking, she grabs a sock fr

om the drawer, puts it back, and then grabs another sock from the drawer. What is the probability that both socks she grabbed were white?
A. 3/25

B. 3/5

C. 12/10

D. 9/25
Mathematics
2 answers:
gayaneshka [121]3 years ago
8 0

3/25 just took the quiz.

gtnhenbr [62]3 years ago
5 0

Answer:

Step-by-step explanation:

3/25

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Pls help. I need the explanations too.
sweet-ann [11.9K]

Answer:

a- about 3$

b-about 8$

c-about .04

Step-by-step explanation:

a-100.8/35=2.88

2.88 is around 3

b-49.2/6=8.2

8.2 is close to 8

c-.78/20=.039

.039 is the nearest to .04

4 0
3 years ago
50/22 rounded to the hundredth
Fynjy0 [20]

Divide 50 by 22: 2.27272727...

Round up to hundredth and your final answer is 2.27

hope that helps :)

3 0
3 years ago
a washer and dryer cost $586 combined. the washer costs $64 less than the dryer. what is the cost of the dryer?
oksano4ka [1.4K]
Hello!

*I'm not very good at algebra, so I am not 100% sure this is correct!*

w = cost of washer

d = cost of dryer

w + d = $586

w = d - 64

d - 64 + d = 586

2d = 586 + 64

2d = 650

d = 650 / 2 = 325

586 - 325 = 261

Check 325 - 261 = 64

So, the dryer costs $325 and because the washer is $64 less than the dryer, it costs $261.

7 0
3 years ago
For a school play, 739 tickets valued at $857 were sold. Some cost $1 and others cost a $1.50. How many $1 tickets were sold?
balu736 [363]

Answer:

503 $1 tickets sold.

Step-by-step explanation:

Use two equations  

Let x = number of $1 tickets sold  

Let y = number of $1.50 tickets sold  

x + y = 739  

1x + (1.5)y = 857  

First equation ==> y = 739 - x  

Plug this into the second equation  

x + (1.5)(739 - x) = 857  

x + 1108.5 - 1.5x = 857  

- 0.5x = -251.5  

x = 503  

There were 503 $1 tickets sold.  

To find the number of $1.50 tickets, just plug this value of x into either one of the equations.  

(503) + y = 739       (739 - 503 = 236)

y = 236  

There were 236 $1.50 tickets sold.

3 0
3 years ago
An airline claims that the no-show rate for passengers is less than 5%. In a sample of 420 randomly selected reservations, 19 we
aleksandr82 [10.1K]

Answer:

An airline claims that the no-show rate for passengers is less than 5%. In a sample of 420 randomly selected reservations, 19 were no-shows. At α=0.01, test the airline's claim. State the sample percentage and round it to three decimal places.

State the hypotheses.

State the critical value(s).

State the test statistics.

State the decision

State the conclusion.

3 0
2 years ago
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