Answer:
E) Either anaphase I or II
Explanation:
Failure of segregation of homologous chromosomes during anaphase I or failure of segregation of sister chromatids during anaphase II leads to the presence of the abnormal number of chromosomes in resultant gametes. In the given example, the egg mother cell with 48 chromosomes (24 pairs) would enter meiosis I but the failure of one pair of homologous chromosomes to segregate from each other followed by normal meiosis II would result in the formation of two gametes with one extra chromosome and two gametes with one less chromosome.
On the other hand, if the nondisjunction occurs at anaphase II of meiosis II, two normal gametes, one gamete with one extra chromosome and one gamete with one less chromosome will be formed. Therefore, nondisjunction at anaphase I or anaphase II would have resulted in the production of eggs with one extra chromosome.
1.Beak for catching prey
2.Wings to fly away from danger
3. Ability to balance
Answer:
<h2>The Infusion Nurses Society (INS) classifies a solution as isotonic if its tonicity falls within (or near) the normal range for blood serum-between 280 and 300 mOsm/liter. A hypotonic solution has an osmolarity less than 280 mOsm/liter, and a hypertonic solution has an osmolarity greater than 300 mOsm/liter.</h2>
<h2>Hopefully u will satisfy with my answer..!!</h2>
<h2>Have a nice day ahead dear..!!</h2>
They are called
a. sunspots
A light-year is how astronomers measure distance in space, hope this helps ^^
