How would you find the area in this regular polygon

Mathematics

1 answer:

Olegator [25]3 years ago

4 0

This is a pentagon, with five equal central angles. Each central angle is 360 degrees/5 = 72 degrees.

The pentagon has five pie-shaped pieces, each with an angle of 72 degrees and two other angles, which are equal, of 54 degrees.

The "base" of each such triangular (pie-shaped) pieces is 5.

Use this info to find the area of ONE of these pieces.

Then multiply your result by 5 to obtain the total area of this pentagon.

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Please help with question A and show work!! thank you

Digiron [165]

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8 0

3 years ago

Find the zeros of f(x) = x^2+5x-6. A. {-2,3} B. {-6,1} c. {-2,-3} D. {-6,-1}

Arisa [49]

Answer:

x^2+5x-6

a = 1 b = 5 and c = -6

Using the quadratic formula:

x = [-5 +- sq root (25 -4 * 1 *-6) ] / 2 * 1

x = [-5 +- sq root (49)] / 2

x = [-5 +- 7] / 2

x1 = 1

x2 = -6

Step-by-step explanation:

7 0

3 years ago

Write an equation in slope-intercept form of the line that bisects the angle formed by BA and BC

slega [8]

Given:

Angled formed by ray BA and ray BC is 90 degrees.

To find:

The equation of line that bisects the angle formed by ray BA and ray BC.

Solution:

If a line bisects the angle formed by ray BA and ray BC, then it must be passes through point B and makes angles of 45 degrees with ray BA and ray BC.

It is possible if the line passes though point B(-1,3) and other point (-2,4).

Equation of line is

$y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)$