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STatiana [176]
2 years ago
7

Can someone help me with this problem?

Mathematics
1 answer:
Jobisdone [24]2 years ago
6 0

The length of the rope Kurt started with is 13 1/3 inches

<h3>Calculating lengths </h3>

From the question, we are to determine the total length of the rope

From the given information,

The first piece was 4 4/5 inches long

and

The second piece was 8 1/2 inches long

Then,

The length of the rope Kurt started with will be

4 4/5 + 8 1/2

4\frac{4}{5} + 8\frac{1}{2}

First, convert the fractions into improper fractions

\frac{24}{5} + \frac{17}{2}

The Lowest common multiple (LCM) of the denominators is 10.

Then, we get

\frac{(2\times 24) + (5 \times 17)}{10}

= \frac{48 + 85}{10}

= \frac{133}{10}

= 13 \frac{1}{3}

Hence, the length of the rope Kurt started with is 13 1/3 inches.

Learn more on Calculating lengths here: brainly.com/question/26496891

#SPJ1

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We need a sample size of least 119

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

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The margin of error is:

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95% confidence level

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At least n, in which n is found when M = 0.09

We don't know the proportion, so we use \pi = 0.5, which is when we would need the largest sample size.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.09 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.09\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.09}

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4 years ago
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Subtracting Eqn 2 from Eqn 1

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