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oksano4ka [1.4K]
2 years ago
6

) The gym teacher divided a class into four teams with 7 students per team. How many students are in the class?

Mathematics
2 answers:
Andreas93 [3]2 years ago
5 0

Answer:

28 students

Step-by-step explanation:

7 times 4 = 28

there are are seven students in 4 teams, so that means there are 4 groups of seven, and you multiply them together to get how many students in the class

Akimi4 [234]2 years ago
5 0

Answer:

28

Keyword(s):

divided, four, 7, per team, how many

Step-by-step explanation:

7 × 4 = 28

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A gas pump measures volume of gas to the nearest 0.01 gallon. Which measurement shows an appropriate level of precision for the
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Answer:

12.3 Gallons

Step-by-step explanation:

Options of the question:-

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Option D is the answer :-

As the least count or zero error is 0.1 so it can measure only upto one decimal place so answer will be 12.3

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2 years ago
Kala bought two types of cheese at a deli. She bought 0.50 pound of American cheese and 1.25 pounds of Swiss cheese. The bar dia
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3 years ago
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16) Please help with question. WILL MARK BRAINLIEST + 10 POINTS.
Katyanochek1 [597]
We will use the sine and cosine of the sum of two angles, the sine and consine of \frac{\pi}{2}, and the relation of the tangent with the sine and cosine:

\sin (\alpha+\beta)=\sin \alpha\cdot\cos\beta + \cos\alpha\cdot\sin\beta

\cos(\alpha+\beta)=\cos\alpha\cdot\cos\beta-\sin\alpha\cdot\sin\beta

\sin\dfrac{\pi}{2}=1,\ \cos\dfrac{\pi}{2}=0

\tan\alpha = \dfrac{\sin\alpha}{\cos\alpha}

If you use those identities, for \alpha=x,\ \beta=\dfrac{\pi}{2}, you get:

\sin\left(x+\dfrac{\pi}{2}\right) = \sin x\cdot\cos\dfrac{\pi}{2} + \cos x\cdot\sin\dfrac{\pi}{2} = \sin x\cdot0 + \cos x \cdot 1 = \cos x

\cos\left(x+\dfrac{\pi}{2}\right) = \cos x \cdot \cos\dfrac{\pi}{2} - \sin x\cdot\sin\dfrac{\pi}{2} = \cos x \cdot 0 - \sin x \cdot 1 = -\sin x

Hence:

\tan \left(x+\dfrac{\pi}{2}\right) = \dfrac{\sin\left(x+\dfrac{\pi}{2}\right)}{\cos\left(x+\dfrac{\pi}{2}\right)} = \dfrac{\cos x}{-\sin x} = -\cot x
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3 years ago
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a parallel line to that one above, will have the same exact slope, since parallel lines have the same slope.

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