Step-by-step explanation:
I assume that "ground" is at 0 ft height. which is in an actual scenario not airways the case.
y = -16x² + 64x + 89
shows us that the tower is 89 ft tall (the result for x = 0, at the start).
anyway, if the original assumption is correct, then we need to solve
0 = -16x² + 64x + 89
the general solution for such a quadratic equation is
x = (-b ± sqrt(b² - 4ac))/)2a)
in our case
a = -16
b = 64
c = 89
x = (-64 ± sqrt(64² - 4×-16×89))/(2×-16) =
= (-64 ± sqrt(4096 + 5696))/-32 =
= (-64 ± sqrt(9792))/-32
x1 = (-64 + 98.95453501...)/-32 = -1.092329219... s
x2 = (-64 - 98.95453501...)/-32 = 5.092329219... s
the negative solution for time is but useful here (it would be the time calculated back to ground at the start).
so, x2 is our solution.
the rocket hits the ground after about 5.09 seconds.
To work out what the other side is that you times 12 to get to 24 you would do: 24 divided by 12 equals 2 therefore you would do 12 times 2 to get 24
Answer:
C) f(x) = 6.25x + 3
Step-by-step explanation:
In order to know which one of the functions could produce the results in the table we simply need to substitute the number of candy bars for x in the function and solve it to see if it provides the correct total weight shown in the table. If we do this with the functions provided we can see that the only one that provides accurate results would be
f(x) = 6.25x + 3
We can input the # of candies for x and see that it provides the exact results every time as seen in the table.
f(x) = 6.25(1) + 3 = 9.25
f(x) = 6.25(2) + 3 = 15.50
f(x) = 6.25(3) + 3 = 21.75
f(x) = 6.25(4) + 3 = 28
We know that,
Volume of sphere = 4/3πr³
72 = 4/3 × 22/7 × r³
72 × 21/88 = r³
³√17.18 = r
2.58 cm = r
:)
X^9 is the answer to this problem.
