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a_sh-v [17]
3 years ago
14

Which two numbers does the √12 fall between? √4 √9 √16 √25 To answer, type in the box below. To answer √4, you would type square

root 4.
Mathematics
2 answers:
Tcecarenko [31]3 years ago
5 0

Answer:

9 and 16...............................................


emmasim [6.3K]3 years ago
5 0
ANSWER

\sqrt{9} \: and \: \sqrt{16}

EXPLANATION

First, simplify the square roots.

\sqrt{4} = \sqrt{ {2}^{2} } = 2

\sqrt{9} = \sqrt{ {3}^{2} } = 3

\sqrt{16} = \sqrt{ {4}^{2} } = 4

\sqrt{25} = \sqrt{ {5}^{2} } = 5

Let us simplify t
\sqrt{12}
Although 12 is not a perfect square, it contains, a perfect square.

\sqrt{12} = \sqrt{4 \times 3} = \sqrt{4} \times \sqrt{3} = 2 \sqrt{3}

We can now observe that,

3 \: < \: 2 \sqrt{3} \: < \: 4

Therefore,

\sqrt{9} \: < \: \sqrt{12} \: < \: \sqrt{16}

Hence

\sqrt{12}
is between,

\sqrt{9}
and

\sqrt{16}
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Using the continuity concept, since the lateral limits and the numeric value of the function are equal at the point in which the definition changes, the function is continuous.

<h3>What is the continuity concept?</h3>

A function f(x) is continuous at x = a if it is defined at x = a, and:

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The definition of the piecewise function is given by:

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Since the definition of the function changes at x = 2, and the domain of the function has no restrictions, this is the only point in which there may be a discontinuity.

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More can be learned about the continuity concept at brainly.com/question/24637240

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