Answer:
425 or 937
Step-by-step explanation:
First, I listed out all the possible numbers for the first digits, namely, the squares under 10.
1*1=1
2*2=4
3*3=9
Since all the digits have to be different, the first digit cannot be 1 because 1 squared is 1. So that leaves us 4 and 9 to work with, which I tried out one at a time.
Starting with 4:
2 squared is 4.
42
2 times 2 plus 1 equals 5.
425
Starting with 9:
3 squared is 9.
93
2 times 3 plus 1 equals 7.
937
So here we have two numbers that both work and meet the requirements (unless I understood the problem wrong at the part where it says "...the second digit in the 3rd digit on one more than twice the second digit")!
I hope this helped! :D
1) <span>B)3x+6y=22
6x+12y=44
because the equations are equivalent to each other
2*(3x+6y=22) -----> 6x+12y=44
2) </span><span>5x+10y=15 should be multiplied by -2, to get 5x*(-2)=-10x, and x then can be eliminated
</span><span>A)-2</span>
Answer: It's (3,-2)
Step-by-step explanation:
