Answer to your question
The base is X
What are the other stuff then?
2 is the power
3 is the constant
Answer:
0.0221 feet per minute.
Step-by-step explanation:

If the Base Diameter = Height of the Cone
The radius of the Cone = h/2
Therefore,

Rate of Change of the Volume, 
Since gravel is being dumped from a conveyor belt at a rate of 10 cubic feet per minute. Therefore, the Volume of the cone is increasing at a rate of 10 cubic feet per minute.

We want to determine how fast is the height of the pile is increasing when the pile is 24 feet high.
We have:

When the pile is 24 feet high, the height of the pile is increasing at a rate of 0.0221 feet per minute.
This equation is in slope-intercept form of y = mx + b form.
The m represented by the coefficient of the x term
represents the slope and b represents the y-intercept.
So our y-intercept is -4 and we can write this as the ordered pair (0, -4).
Answer:
5.4 m
Step-by-step explanation:
18/3 = x/0.9
0.9(18/3) = x
x = 5.4
Answer:
2
Step-by-step explanation:
3 * -2 = -6
-6 +5 = 1
-2 * -1 = 2