120 / 18 = 20/3
x^3 / xy = x^2 / y
20x^2 / 3y
Answer:
%82.5
Step-by-step explanation:
- The final exam of a particular class makes up 40% of the final grade
- Moe is failing the class with an average (arithmetic mean) of 45% just before taking the final exam.
From point 1 we know that Moe´s grade just before taking the final exam represents 60% of the final grade. Then, using the information in the point 2 we can compute Moe´s final grade as follows:
,
where FG is Moe´s Final Grade and FE is Moe´s final exam grade. Then,
.
So, in order to receive the passing grade average of 60% for the class Moe needs to obtain in his exam:

That is, he need al least %82.5 to obtain a passing grade.
Step-by-step explanation:
sgkwiwbwisbsydjsgs it gsuagia doozy f hddh dish of hi isvsisvsshsjshjsvshvshsissb
I don't have my calculator handy just now. But just looking at that problem, why don't you try +20 and -45 and see if they do the job.