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yulyashka [42]
2 years ago
12

As stream discharge increases ________. only velocity increases velocity, width, and depth increase velocity, width, and depth d

ecrease only depth increases
Physics
1 answer:
nignag [31]2 years ago
5 0

As stream discharge increases, only velocity increases.

<h3>What is discharge?</h3>

The discharge or volume flow rate is defined as the product of the velocity of the fluid and the area of cross- section of the pipe or tube.

Discharge Q = Area A x Velocity V

Q = AV

The discharge is directly proportional to the velocity of the fluid. When discharge increases, velocity is the only physical quantity that can be changed.

Thus, As stream discharge increases, only velocity increases.

Learn more about discharge.

brainly.com/question/25727077

#SPJ1

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A biker to move from speed of 0 m/s to final speed of 25 m/s in 10 s. What is the acceleration of the bike?
Rzqust [24]

Answer:

a = 2.5 m/s²

Explanation:

given,

initial speed = 0 m/s

final speed = 25 m/s

time = 10 s

acceleration of bike is equal to change in velocity per unit time

  a = \dfrac{\Delta v}{t}

  a = \dfrac{v_f-v_i}{t}

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4 0
3 years ago
A moving curling stone, A, collides head on with stationary stone, B. Stone B has a larger mass than stone A. If friction is neg
Kitty [74]

Answer:

The correct answer is option 'c': Smaller stone rebounds while as larger stone remains stationary.

Explanation:

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and the mass of big rock be 'M'

Initial momentum of the system equals

p_i=mv+0=mv

Now let after the collision the small stone move with a velocity v' and the big roch move with a velocity V'

Thus the final momentum of the system is

p_f=mv'+MV'

Equating initial and the final momenta we get

mv=mv'+MV'\\\\m(v-v')=MV'.....i

Now since the surface is frictionless thus the energy is also conserved thus

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Similarly the final energy becomes

E_f=\frac{1}{2}mv'^2+\frac{1}{2}MV'^2\

Equating initial and final energies we get

\frac{1}{2}mv^2=\frac{1}{2}mv'^2+\frac{1}{2}MV'^2\\\\mv^2=mv'^2+MV'^2\\\\m(v^2-v'^2)=MV'^2\\\\m(v-v')(v+v')=MV'^2......(ii)

Solving i and ii we get

v+v'=V'

Using this in equation i we get

v'=\frac{v(m-M)}{(M-m)}=-v

Thus putting v = -v' in equation i  we get V' = 0

This implies Smaller stone rebounds while as larger stone remains stationary.

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The vector's magnitude is the square root of (one component squared) + (the other component squred). The magnitude is non-zero if one component or the other is zero, but not if they both are.
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