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ivanzaharov [21]
3 years ago
15

A 20 kg sled stars at the top of a hill which is 10 m above the bottom and slides a distance of 50 m, ending at the bottom of th

e hill with a speed of 8 m/s. During the slide, the work done by gravity is about
Physics
1 answer:
katrin [286]3 years ago
5 0

Answer:

80 Joules.

Explanation:

Given that a 20 kg sled stars at the top of a hill which is 10 m above the bottom and slides a distance of 50 m, ending at the bottom of the hill with a speed of 8 m/s. During the slide, the work done by gravity is about ?

The parameters given are:

Mass M = 20 kg

Height h = 10 m

Velocity V = 8 m/s

The workdone by gravity will be equal to the total energy

At the bottom of the hill, the total energy will be equal to the maximum kinetic energy.

Maximum K.E = 1/2mv^2

K.E = 1/2 × 20 × 8

K.E = 80J

Therefore, the workdone by the gravity is equal to 80 Joules.

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Here is the correct answer of the given problem above.
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8 0
4 years ago
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A 6 V battery is connected to a 24 ohm resistor to create a circuit. The 6 V battery is then replaced with a 12 V battery. How d
11Alexandr11 [23.1K]

Answer:

1.) The current is doubled

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4.) Distance between Particles (m)

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4 years ago
The acceleration due to gravity on the moon is about 1/6 of the acceleration due to gravity on the earth. A net force F acts hor
uysha [10]

Answer:

c.a_m

Explanation:

We are given that

Acceleration due to gravity on the moon=a_m

Acceleration due to gravity on the earth=a_e

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Net force due to am on an object on moon=F_{net}=ma_m

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During stage 3 - late expanding (of demogrpahic transition model)

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3 0
4 years ago
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Answer:

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