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ivanzaharov [21]
3 years ago
15

A 20 kg sled stars at the top of a hill which is 10 m above the bottom and slides a distance of 50 m, ending at the bottom of th

e hill with a speed of 8 m/s. During the slide, the work done by gravity is about
Physics
1 answer:
katrin [286]3 years ago
5 0

Answer:

80 Joules.

Explanation:

Given that a 20 kg sled stars at the top of a hill which is 10 m above the bottom and slides a distance of 50 m, ending at the bottom of the hill with a speed of 8 m/s. During the slide, the work done by gravity is about ?

The parameters given are:

Mass M = 20 kg

Height h = 10 m

Velocity V = 8 m/s

The workdone by gravity will be equal to the total energy

At the bottom of the hill, the total energy will be equal to the maximum kinetic energy.

Maximum K.E = 1/2mv^2

K.E = 1/2 × 20 × 8

K.E = 80J

Therefore, the workdone by the gravity is equal to 80 Joules.

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Two large parallel metal plates are 1.2 cm apart and have charges of equal magnitude but opposite signs on their facing surfaces
zheka24 [161]

Answer:

E=1100V/m

                                                                     

Explanation:

Given           required           <u>solution</u>

V=6.6v         E=?                   V=Ed ;    V is the potential difference between                                                              

d=D/2=1.2cm/2=0.6cm=0.006m             the   halfway                  

                                                               E is the electric field between the two                                                                              

                                                                       plates.

                                                              d is the distance between the halfway.

So we can use the above formula to calculate the electric field.

    V=Ed   from this E=V/d  substitute the values from the given equation.

E=6.6v/0.006m

E= 1100 v/m

                                                                     

3 0
3 years ago
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