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ivanzaharov [21]
3 years ago
15

A 20 kg sled stars at the top of a hill which is 10 m above the bottom and slides a distance of 50 m, ending at the bottom of th

e hill with a speed of 8 m/s. During the slide, the work done by gravity is about
Physics
1 answer:
katrin [286]3 years ago
5 0

Answer:

80 Joules.

Explanation:

Given that a 20 kg sled stars at the top of a hill which is 10 m above the bottom and slides a distance of 50 m, ending at the bottom of the hill with a speed of 8 m/s. During the slide, the work done by gravity is about ?

The parameters given are:

Mass M = 20 kg

Height h = 10 m

Velocity V = 8 m/s

The workdone by gravity will be equal to the total energy

At the bottom of the hill, the total energy will be equal to the maximum kinetic energy.

Maximum K.E = 1/2mv^2

K.E = 1/2 × 20 × 8

K.E = 80J

Therefore, the workdone by the gravity is equal to 80 Joules.

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How does a multicellular organism develop
Klio2033 [76]

Answer:

A multicellular organism develops from a single cell called (the zygote)

Explanation:

This is because many different cell types, organized into tissues and organs. Development involves cell division, body axis formation, tissue and organ development, and cell differentiation

7 0
3 years ago
You stand 17.5 m from a wall holding a tennis ball. You throw the tennis ball at the wall at an angle of 22.5∘ from the ground w
RUDIKE [14]

The height of the ball would be 4.32 m

<u>Explanation:</u>

Given-

Distance from the ball, s = 17.5 m

Angle of projection, θ = 22.5°

Initial speed, u = 24.5 m/s

Height, h = ?

Let t be the time taken.

Horizontal speed, u_{x} = u cosθ

                                   = 24.5 * cos 22.5°

                                   = 24.5 * 0.924

                                   = 22.64 m/s

Vertical velocity, u_{y} = u sinθ

                                 = 24.5 * sin 22.5°

                                 = 24.5 * 0.383

                                 = 9.38 m/s

We know,

x = u * cos (theta) * t

17.5 = 22.64 * t\\\\t = 0.77s

To calculate the height:

h = ut - \frac{1}{2}gt^2

h =  u sin (theta)t - \frac{1}{2} gt^2

h = 9.38 * 0.77 - \frac{1}{2} * 9.8 * (0.77)^2\\ \\h = 7.22 - 2.90\\\\h = 4.32m\\

Therefore, height of the ball would be 4.32 m

3 0
4 years ago
(c) The driver of a car traveling at a speed of 17 m/s slams on the brakes and comes to a stop in 3 s. If we assume that the spe
liubo4ka [24]

Answer:

v_{avg}=8.5\ m/s

Explanation:

given,

initial speed of the car, v₁ = 17 m/s

final speed of the car, v₂ = 0 m/s

car stops in time = 3 s

we need to calculate average speed

v_{avg}=\dfrac{v_1 + v_2}{2}

v_{avg}=\dfrac{17 + 0}{2}

v_{avg}=\dfrac{17}{2}

v_{avg}=8.5\ m/s

average speed of the car during interval of 3 s is 8.5 m/s

5 0
3 years ago
Pls help !!
masha68 [24]

Answer:

Power is the rate at which work is done

Explanation:

Power is the rate at which work is done. Power is measured in watts.

Work is the use of force to move an object. Work is measured in joules.

5 0
3 years ago
Read 2 more answers
If a magnet repels a metal object what can you say about the pole of the magnet and the pole of the object?
sleet_krkn [62]
Poles are the same D is the right answer
7 0
3 years ago
Read 2 more answers
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