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zaharov [31]
2 years ago
7

What's the basicity of HBr?​

Chemistry
1 answer:
Rus_ich [418]2 years ago
8 0

<em>Hydrogen bromide</em>

<em>Basicity (pKb) ~23</em>

<em>mark </em><em>me </em><em>as </em><em>brainliest </em>

<em>#</em><em>◌⑅⃝●♡⋆♡</em><em>Nåmřāthā </em><em>♡⋆♡●⑅◌</em>

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A mutation produces a bright Orange moth in the population of green moths. The moths live ia a green forest would this mutation
Mamont248 [21]
No it will not be passed on. As the question states the moths live in a green forest so the green moths have camouflage, which is a big advantage. But the orange moth doesn’t and will very easily be spotted by predators(will die very soon probably before reaching its reproductive period) thus the mutation wont be passed on.

Hope this helps:)
7 0
4 years ago
wegener used that the same dinosaur fossils have been found in different continents to support his theory of continental drift.
shutvik [7]
The answer to this would be true.
4 0
3 years ago
Which of the following is true about an abiotic resource?
aev [14]

Answer:

B. It is a nonliving resource.

Explanation:

The definition of abiotic is "nonliving," and examples of abiotic resources may include soil or water.

5 0
3 years ago
5. calculate the percentage of water of crystallization in blue vitriol (copper sulphate pentahydrate), cuso4.5h2o
ki77a [65]

The percentage of water of crystallization in blue vitriol is 36.07%.

M(H₂O) = 2Ar(H) + Ar(O) x g/mol

M(H₂O) = 2 + 16 x g/mol

M(H₂O) = 18 g/mol; molar mass of water

M(CuSO₄·5H₂O) = Ar(Cu) + Ar(S) + 4Ar(O) + 5Mr(H₂O) x g/mol

M(CuSO₄·5H₂O) = 63.5 + 32 + 64 + 90 x g/mol

M(CuSO₄·5H₂O) = 249.5 g/mol; molar mass of copper sulphate pentahydrate

The percentage of water: 5M(H₂O) / M(CuSO₄·5H₂O) x 100%

The percentage of water: 90 g/mol / 249.5 g/mol x 100%

The percentage of water = 36.07%

More about blue vitriol: brainly.com/question/8895853

#SPJ4

5 0
1 year ago
Read 2 more answers
(45 pts) In which reaction is carbon reduced?
Sidana [21]

Answer:

Reductio is gain of electrons, while oxdation is loss. The oxidtion states of carbon in the reaction will show either of oxidation or reduction occurrence.

C_{2} H_{2}(g)  +H_{2} (g) → C_{2} H_{4}(g)

Explanation:

Electrons displacement is explained for each reaction below:

  1. +2 to +4 = loss of 2 more lectrons-------oxidation
  2. +4 throughout reaction----no exchange of electrons
  3. -4 to +4 =  loss of 4 electrons-----oxidation
  4. 0 to -2 = gain of 2 electrons-----reduction
5 0
3 years ago
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