Can you be a little more clear, so I can get a better understanding?
H = 2f / (m+1)
[multiply by (m+1)]
h(m+1) = 2f
[divide by 2]
f = (h (m + 1)) / 2
3b / (b+2) = 12 / (b+2)
[multiply by (b+2)]
3b = 12
[divide by 3]
b = 4
3 / (6x + 1) / 2 = 8 / (x + 4) / 3
[multiply both denominators to mike one denominator]
3 / 8(6x+1) = 8 / 3(x+4)
[expand brackets]
3 / (48x + 8) = 8 / (3x + 12)
[multiply by (48x + 8)]
3 = 8(48x + 8) / (3x+12)
[multiply by (3x+12)]
3(3x +12) = 4(48x + 8)
[simplify]
9x + 36 = 192x + 32
173x = 4
x = 4 / 173
Answer:
the answer is 87
Step-by-step explanation:
Go and ask your counsler that if you don't get tutoring then you fear that you will fail your class
By definition
... sec(θ) = 1/cos(θ) . . . . trig identity
... sec(θ) = 1/(9/10) . . . . substitute the given value, then simplify to ...
... sec(θ) = 10/9
