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2 years ago

If y= 2f(g(x)), then d^2y/dx^2=

Mathematics

1 answer:

Lina20 [59]2 years ago

8 0

Use the chain rule to differentiate both sides of the given equation with respect to $x$ :

$y = 2 f(g(x))$

$\dfrac{dy}{dx} = y' = 2 f'(g(x)) g'(x)$

Differentiate again with the product and chain rules to get the second derivative :

$\dfrac{d^2y}{dx^2} = y'' = \boxed{2 f'(g(x)) g''(x) + 2 f''(g(x)) g'(x)^2}$

(D)

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Please help me answer this

Alja [10]

Answer:

Brand A

Step-by-step explanation: Brand A because y=50x+100 and that equals 150x. For brand B y=25x+200 and that equals 225x. So Brand A is lower.

3 0

3 years ago

IK I'VE POSTED THIS QUESTION SOOO MANY TIMES BUT I NEED HELO, SOMEONE PLSSSSSSSSS HELP

marta [7]

I would love to help! However I'm not sure what I'm supposed to be helping with. I could just be daft, but it isn't clear what you need from me.

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3 years ago

Read 2 more answers

Assume Jones Manufacturing begins January with 10 units of inventory that cost $10 each. During January, the following purchases

Ratling [72]

Answer:

10.44

Step-by-step explanation:

The weighted average cost per unit method seeks to get the cost of goods sold as an average of all cost of goods in the inventory as at the time of sales.

Part of its objective is to strike a balance between the (FIFO and LIFO) inventory valuation methods.

Beginning inventory ( Jan) = 10 units

Cost of beginning inventory per unit = $10

Total cost of beginning inventory = Cost * Number of units

In this case (10*$10) = $100

Additional purchase (Jan 5) = 8 units

Cost of additional purchase per unit = $11

Total cost of additional purchase = 8 * $11 = $88

Weighted average cost per unit at the time 11 units are sold on January 7 = Total cost of units at that time / number of units available at that time.

= ($100+ $88) / (10+8)

= 188/18

=10.44 (approximated to 2 decimal places)

I hope this helps make the concept clear.

7 0

4 years ago

I ready scientific notation help

Airida [17]

The required value is $2\times10^9$

Step-by-step explanation:

Weight of ants = $4\times10^{-3}$

Weight of elephant= $8\times10^6$

We need to find, the total weight of about how many ants equals to the weight of an oversized elephant.

The equation given is:

$4\times10^{-3} \times a = 8\times10^6$

We need to find a:

Solving:

$4\times10^{-3} \times a = 8\times10^6\\a=\frac{8\times10^6}{4\times10^{-3}}\\if \,\,10^a/10^-b \,\,then\,\, 10^{a+b}\\a=2\times10^{6+3} \\a=2\times10^9$

So, the required value is $2\times10^9$

Keywords: Scientific Notation

Learn more about Scientific Notation at:

#learnwithBrainly

4 0

3 years ago

30 points!!!!

RSB [31]

Answer:

Part A is ≤ means less than OR equal to. < only means less than

Part B is 9

Step-by-step explanation:

A: Because it would equal 19, and 19 is equal than 19. 4(5) - 1 would equal 19, which is equal to 19, and not less than. ≤ means less than or equal to. < means less than. So its not true.

B: 47 - 2, 45. Then 5 x 9 equals 45. So 5 x 9 equals 45, then add 2 would equal 47.

6 0

2 years ago

If y= 2f(g(x)), then d^2y/dx^2=​

If y= 2f(g(x)), then d^2y/dx^2=