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Helga [31]
1 year ago
15

Bobs snowplow business charges 300$ per season plus 10$ for each walkway shoveled, while mikes snow removal charges 250$ per sea

son plus 15$ per walkway.
using technology, how many walkways must be shoveled to result in equal billing from both companies?
Mathematics
1 answer:
slamgirl [31]1 year ago
6 0

The number of walkways that must be shoveled to result in <u>equal billing</u> from both companies is 10

<h3>Calculating cost</h3>

From the question, we are to determine how many walkways must be shoveled to result in equal billing from both companies

Let the number of walkways be x

From the given information,

Bobs snowplow business charges 300$ per season plus 10$ for each walkway shoveled

∴ If x walkways are shoveled

the billing will be $300 + $10x

For Mikes snow removal

Mikes snow removal charges 250$ per season plus 15$ per walkway

∴ If x walkways are shoveled

the billing will be $250 + $15x

Now, we are to determine the value of x for which the billings from both companies will be equal,
That is,

$300 + $10x = $250 + $15x

$15x - $10x = $300 - $250

$5x = $50

x = $50 / $5

x = 10

Hence, the number of walkways that must be shoveled to result in <u>equal billing</u> from both companies is 10.

Learn more on Calculating cost here: brainly.com/question/2638969

#SPJ1

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Answer:

P=0.147

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We have to find the probability, that at least 9 trucks from 16 have good brakes, however fewer than 12 trucks from 16 have good brakes. That actually means the the number of trucks with good brakes has to be 9, 10 or 11 trucks from 16.

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Answer:

\text {CI} = (60.54, \: 81.46)\\\\

Therefore, we are 95% confident that actual mean savings for a televisit to the doctor is within the interval of ($60.54 to $81.46)

Step-by-step explanation:

Let us find out the mean savings for a televisit to the doctor from the given data.

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=AVERAGE(number1, number2,....)

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\bar{x} = \$71  

Let us find out the standard deviation of savings for a televisit to the doctor from the given data.

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\text {confidence interval} = \bar{x} \pm MoE\\\\

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MoE = t_{\alpha/2}(\frac{s}{\sqrt{n} } ) \\\\MoE = 2.093\cdot \frac{22.35}{\sqrt{20} } \\\\MoE = 2.093\cdot 4.997\\\\MoE = 10.46\\\\

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\text {CI} = \bar{x} \pm MoE\\\\\text {CI} = 71 \pm 10.46\\\\\text {CI} = 71 - 10.46, \: 71 + 10.46\\\\\text {CI} = (60.54, \: 81.46)\\\\

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