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AysviL [449]
2 years ago
10

Suppose you select four cards at random from a standard deck of playing cards and end up with a macrostate of four deuces. How m

any microstates are associated with this macrostate?
Mathematics
1 answer:
dangina [55]2 years ago
6 0

Answer:

There are four microstates associated with the macrostate

Step-by-step explanation:

Macrostate is the largest possible microstate outcome in an event.

There are four deuces in a standard deck of playing cards, these include;

two heart, two spade, two club and two diamond.

Thus, when a macrostate of four deuces are selected, the microstates are two heart, two spade, two club and two diamond.

The microstates are four.

Therefore, there are four microstates associated with the macrostate.

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denis23 [38]

Answer:

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Step-by-step explanation:

4 0
3 years ago
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Matt uses a compass and straightedge to construct parallel lines. Annie uses technology. In your own words describe how Matts co
ra1l [238]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

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5 0
2 years ago
1. A family is building a circular fountain in the backyard. The yard is rectangular and measures 10x by 15x and the fountain is
sp2606 [1]
1. The remaing area of the yard will be found as follows:
Area of the yard

A1=length*width=10x*15x=150x^2 yd^2

area of the fountain
A2=πr²
A2=π(4x)²
=50.266x^2

The remaining area will be:
A=150x^2-50.266x^2
A=99.735x^2 yd^2


2] Area left for bleachers, restrooms and other parts of the stadium will be as follows:
Area of the lot is:
A1=length*width
A1=8x×12x= 96x^2 

Area of the field
A2=length×width
A2=3x×6x=18x^2

Hence the remaining area will be:
A1-A2
=96x^2-18x^2
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7 0
2 years ago
Complete the missing terms in the sequence<br> 6, 3, 0,<br><br><br> ,
Alborosie

Answer:

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Step-by-step explanation:

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5 0
2 years ago
Derive <br><br>Sinxy = x² + 2xy​
bogdanovich [222]

Answer:

    \frac{dy}{dx} = \frac{2x +2 y- ycosxy}{x(cosxy-2)}

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given

        sin xy = x² + 2xy ...(i)

Apply

       \frac{d}{dx} UV = U^{l} V + U V^{l}

     \frac{d}{dx} x^{n} = nx^{n-1}

Differentiating equation (i) with respective to 'x', we get

      cosxy \frac{d}{dx} (xy) = 2x + 2( x\frac{dy}{dx} + y(1))

      cosxy  (x\frac{dy}{dx} +y(1)) = 2x + 2( x\frac{dy}{dx} + y(1))

     cosxy  (x\frac{dy}{dx}) + ycosxy = 2x + 2( x\frac{dy}{dx}) +2 y)

   cosxy  (x\frac{dy}{dx}) - 2( x\frac{dy}{dx}) = 2x +2 y- ycosxy

   (cosxy-2)  (x\frac{dy}{dx})  = 2x +2 y- ycosxy

       \frac{dy}{dx} = \frac{2x +2 y- ycosxy}{x(cosxy-2)}

8 0
2 years ago
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