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MAXImum [283]
2 years ago
9

Take a square sheet of paper 20 cm by 20 cm, cut identical squares from each corner, and fold up the flaps to make a box (withou

t a lid). What is the volume of the box? What different volumes can you make by varying the size of the squares you cut of?
Task: what is the maximum possible volume of this type of box that can be made from a 20 cm by 20 cm square of paper?
Mathematics
1 answer:
iris [78.8K]2 years ago
3 0

The maximum possible volume of this type of box that can be made from a 20 cm by 20 cm square of paper is 512cm³.

<h3>How to calculate the volume?</h3>

From the information, when the side of 1cm are cut, this will become an open box. The volume will be:

= 18 × 18 × 1

= 324cm³

Also, when 2cm is cut, the volume will be:

= 16 × 16 × 2

= 512cm³

Learn more about volume on:

brainly.com/question/1972490

#SPJ1

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Hazel McCurry offered $149,400 for a home that had been priced at $439,500. The seller agreed to the offer. If she made a $44,00
vredina [299]
149,400-44,000
=$105,400
8 0
3 years ago
Use the distributive property to solve the equation 28 - (3x + 4) = 2(x + 6) + 5
Shalnov [3]
1.) 28-3x-4= 2x+12+x
2.) 24-3x= 3x+12
3.)24-6x=12
4.)-6x=-12
5.)x=2
7 0
3 years ago
How can I solve (b)?
dsp73
90/3 parts of silver = 30 times multiplied by
tin = 12 × 30 = 360g
lead = 8 × 30 = 240g

12.5 / 23 = 0.5434 parts per metal

tin = 12 × 0.5434 = 6.5kg
lead = 8 × 0.5434 = 4.5kg
silver = 3 × 0.5434 = 1.5kg
5 0
3 years ago
Solve on the interval [0/2pi]<br><br> 1-cos(theta) = (1/2)
Airida [17]

Answer:

Final answer is x=\frac{\pi}{3} and x=\frac{5\pi}{3}.

Step-by-step explanation:

Given equation is 1-\cos\left(\theta\right)=\frac{1}{2}

Now we need to find the solution of  1-\cos\left(\theta\right)=\frac{1}{2} in given interval [0, 2\pi ].

1-\cos\left(\theta\right)=\frac{1}{2}

-\cos\left(\theta\right)=\frac{1}{2}-1

-\cos\left(\theta\right)=-\frac{1}{2}

\cos\left(\theta\right)=\frac{1}{2}

which gives x=\frac{\pi}{3} and x=\frac{5\pi}{3} in the given interval.

Hence final answer is x=\frac{\pi}{3} and x=\frac{5\pi}{3}.

6 0
3 years ago
a flag pole that is 8 feet tall casts a shadow that is 6 ft long a nearby tree casts a shadow that is 21 ft long. How tall is th
Andru [333]

Answer:

The tree is 28 feet tall.

Step-by-step explanation:

It is given that:

Height of flag pole = 8 feet

Shadow of flag pole = 6 feet

Ratio of height to shadow = 8 : 6

Shadow of nearby tree = 21 feet

Height of nearby tree = x

Ratio of height to shadow = x : 21

8 : 6 :: x : 21

Product of means = Product of extremes

6x = 8*21

6x = 168

Dividing both sides by 6

\frac{6x}{6}=\frac{168}{6}\\x=28

Therefore,

The tree is 28 feet tall.

7 0
3 years ago
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