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3 years ago

6

What is the range of the function in the graph?

1 answer:

ziro4ka [17]3 years ago

7 0

Answer:

b=70

Step-by-step explanation:

The range is the value that the output takes

In this graph, the output is constant at 70

The output value is b

b=70

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A student made a list of questions to gather data about a local movie theater. She will ask a sample of her classmates to answer

Wewaii [24]

Answer: A D E

Step-by-step explanation:

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2 years ago

So yeah if someone can help me with

Law Incorporation [45]

Answer:

y = x - 5

Step-by-step explanation:

The equation of the line parallel to the line $ax + by + c_1 = 0$ is $ax + by + c_2 = 0$ .

That is, equations of parallel lines differ only by constant.

The given equation is $y = x + 4$

This is written as $x - y + 4 = 0$

Therefore, the equation of the line parallel to this line is given by $x - y + c = 0$

The value of c is determined using the point given.

Substituting the point (3,-2) we get:

$3 + 2 + c = 0$

$\implies c = -5$

Therefore, the equation of the line becomes y = x - 5.

6 0

3 years ago

[30 POINTS] Please help!!!

Len [333]

Answer:

Part 1) $y=1.5x+5$

Part 2) $y=-(2/3)x-(11/3)$

Part 3) $y=0.25x+2.75$

Part 4) $y=-2x+5$

Part 5) $y=0.5x-1$

Part 6) The graph in the attached figure

Step-by-step explanation:

Part 1) we have

$m=3/2=1.5$

$point(-2,2)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-2=1.5(x+2)$

$y=1.5x+3+2$

$y=1.5x+5$

Part 2) we know that

If two lines are perpendicular

then

the product of their slopes is equal to minus one

so

$m1*m2=-1$

the slope of the line 1 is equal to

$m1=1.5$

Find the slope m2

$1.5*m2=-1$

$m2=-2/3$

Find the equation of the line 2

we have

$m2=-2/3$

$point(-7,1)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-1=(-2/3)(x+7)$

$y=-(2/3)x-(14/3)+1$

$y=-(2/3)x-(11/3)$

Part 3) we have

$m=1/4=0.25$

$point(1,3)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-3=0.25(x-1)$

$y=0.25x-0.25+3$

$y=0.25x+2.75$

Part 4) we have

$m=-2$

$b=5$ -----> y-intercept

we know that

The equation of the line into slope intercept form is equal to

$y=mx+b$

substitute the values

$y=-2x+5$

Part 5) we have that

The slope of the line 4 is equal to $-2$

so

the slope of the line perpendicular to the line 4 is equal to

$-2*m=-1\\m=(1/2)=0.5$

therefore

in this problem we have

$m=0.5$

$point(-2,-2)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y+2=0.5(x+2)$

$y=0.5x+1-2$

$y=0.5x-1$

Part 6)

using a graphing tool

see the attached figure

3 0

3 years ago

The weight of 1000 identical samples of a substance is 1 pound. What is the weight of 100 samples?

alex41 [277]

The answer is 0.1 lbs. Or 1/10 lbs.

Hope this helps!

8 0

3 years ago

Read 2 more answers

Expand and simplify 4(2x+3)+4(3x+2)

REY [17]

8x+12+12x+8
20x+20
The final answer is 20x+20

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3 years ago