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Artist 52 [7]
3 years ago
6

If the total area of a dartboard is 40,000 mm2 and the area of the second ring is 17,500 mm2, what is the probability of landing

in that second ring?
A.44%

B.40%

C.17%

D.50%
Mathematics
2 answers:
Klio2033 [76]3 years ago
7 0
Your answer is (A)44%. Hope this helps
Basile [38]3 years ago
4 0
A) 44 percent is the correct answer
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What fractional part of a pound is an ounce
Andre45 [30]

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There are 16 English ounces in an English pound. There are 12 troy ounces in a troy pound.</span>

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2 years ago
55.8 is 62% of what number?
zhenek [66]
90

55.8 /? = 62/100
55.8 x 100= 62 x ?
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3 years ago
A manufactured lot of buggy whips has 20 items, of which 5 are defective. A random sample of 5 items is chosen to be inspected.
dimulka [17.4K]

Answer:

a. 39.55%

b. 44.02%

Step-by-step explanation:

We have the following data:

n = 5

x = 1

p = 5/20 = 0.25

to. If the sampling is done with replacement.

We apply the binomial distribution formula, which is as follows:

P = nCx * (p ^ x) * ((1-p) ^ (n-x))

Where nCx, is a combination, and is equal to:

nCx = n! / x! * (n-x)!

replacing we have:

5C1 = 5! / 1! * 4! = 5

replacing in the main formula:

P = 5 * (0.25 ^ 1) * ((1- 0.25) ^ (5-1))

P = 0.3955

that is, without replacing the probability is 39.55%

b. if the sampling is done without replacement.

Here it is a little different from the previous one, but what you should do is calculate three cases,

the first was the one at point a, when n = 5 and x = 1

5C1 = 5! / 1! * 4! = 5

the second is when n = 20 and x = 5, this is all possible scenarios.

20C5 = 20! / 5! * 15! = 15504

and the third is when n = 15 (20-5) and x = 4 (5-1), which corresponds to the cases when none were damaged

15C4 = 15! / 4! * 11! = 1365

In the end, it would be:

P = (5C1 * 15C4) / 20C5

Replacing:

P = 5 * 1365/15504

P = 0.4402

Which means that without replacing the probability is 44.02%

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answer 143.00 Step-by-step explanation:

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