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sample 1: it has phosphorus, main chemical compund
75% black 25% white ( 25% pure black, 50% hybrid and 25% white)
Answer:
Explanation:
We know that the sample is 35% adenine, which tells us that it is also 35% thymine. We know that cytosine and guanine pair together and will be present in equal amounts, so we can divide this final total by 2 to find our answer. The sample is 35% adenine, 35% thymine, 15% guanine, and 15% cytosine.
The answer is 9%.
To calculate this we will use some <span>formulas of the Hardy-Weinberg principle:
</span><span>p² + 2pq + q² = 1 and <span>p + q = 1
where:
</span></span>
<span>p - the frequency of the A allele.
q - the frequency of the a allele.</span>
p² - the frequency of dominant homozygote (with AA genotype)
2pq - the frequency of heterozygote (with Aa genotype)
<span>q² - the frequency of recessive homozygote (with aa genotype)</span>
<span>We know:</span>
p = 70% = 70/100 = 0.7
q = 30% = 30/100 = 0.3
We need to calculate the frequency of the genotype aa:
q² = ?
Since we know the frequency of allele q, it is easy to calculate the frequency of the genotype aa:
q² = 0.3² = 0.09 = 0.09 · 100% = 9%
