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Veseljchak [2.6K]
3 years ago
6

Please help on #18! thank you!

Mathematics
1 answer:
Scrat [10]3 years ago
4 0

the answer for #18 is c

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Solve for x and y. *
bogdanovich [222]

Answer:

beeebooobeeeeeboooooobeeeeebooooooo

Step-by-step explanation:

option a

4 0
2 years ago
NASA launches a rocket at t=0 seconds. Its height, in meters above sea-level, as a function of time is given by h(t)=-4.9t2+64t+
ryzh [129]

Using the vertex of the quadratic equation, it is found that:

The rocket will reach its peak height of 345 meters above sea level at 6.53 seconds.

<h3>What is the vertex of a quadratic equation?</h3>

A quadratic equation is modeled by:

y = ax^2 + bx + c

The vertex is given by:

(x_v, y_v)

In which:

x_v = -\frac{b}{2a}

y_v = -\frac{b^2 - 4ac}{4a}

Considering the coefficient a, we have that:

  • If a < 0, the vertex is a maximum point.
  • If a > 0, the vertex is a minimum point.

In this problem, the equation is given by:

h(t) = -4.9t² + 64t + 136.

The coefficients are a = -4.9 < 0, b = 64, c = 136, hence the instant of the maximum height is given by, in seconds:

t_v = -\frac{64}{2(-4.9)} = 6.53

More can be learned about the vertex of a quadratic equation at brainly.com/question/24737967

#SPJ1

7 0
2 years ago
Write 0.132 as a number
Luden [163]
0.132 written in lowercase:

one hundred thirty-two thousandths


zero point one hundred thirty-two

or, even simpler:

zero point one three two

4 0
2 years ago
Read 2 more answers
Plz help im timed abcdefghijklmnopqrstuvwxyz
lilavasa [31]

Answer:

16(0.5x – 0.75y + 2)

<em>It’s the actual answer, trust me. Choose that option, and tell me if it’s correct and I bet it will be.</em>

<em />

<em>Hope this helps! </em>:)

3 0
2 years ago
1. A right triangle LMN is given where: side MN = 8 side NL (the hypotenuse) =
inessss [21]

Step-by-step explanation:

\underline{ \underline{ \text{Given}}} :

  • Length of MN ( Base ) = 8
  • Length of NL ( Hypotenuse ) = 10

\underline{ \underline{ \text{To \: find}}} :

  • Length of LM ( Perpendicular )

\underline{ \underline{ \text{Using \: pythagoras \: theorem}}} :

\boxed{ \sf{ {Hypotenuse}^{2}  =  {Perpendicular}^{2}  +  {Base}^{2} }}

⤑ \sf{  Perpendicular =  \sqrt{ {(Hypotenuse)}^{2}  -   {(Base)}^{2}  } }

⤑ \sf{ \sqrt{ {(10)}^{2}  -   {(8)}^{2}  } }

⤑ \sf{ \sqrt{100  -  64}}

⤑ \sf{ \sqrt{36}}

⤑ \boxed{ \sf{6\: units}}

\pink{ \boxed{ \boxed{ \tt{Our \: final \: answer :  \boxed{ \underline { \tt{6 \: units}}}}}}}

Hope I helped ! ツ

Have a wonderful day / night ! ♡

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

5 0
2 years ago
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