Answer:k = 10.83 N/m²
Explanation: The angular frequency (ω), spring constant (k) and mass is related by the formulae below
ω = √k/m
But ω = 2πf, where f = frequency.
f = number of oscillations /time taken
Number of oscillations = 14, time taken = 11s
f = 14/11 = 1.27Hz.
ω = 2×22/7×1.27
ω = 7.98 rad/s.
By substituting this parameters into ω = √k/m
Where ω = 7.98rad/s, m = 170g = 170/1000 = 0.17kg.
7.98 = √k/0.17
By squaring both sides
(7.98)² = k/ 0.17
k = (7.98)² × 0.17
k = 10.83 N/m²
The force exerted on his torso by his legs during the deceleration is 4365 N.
<u>Explanation:</u>
Mass of the torso m=45kg
Height of the building s=3.5 m
Decelerating distance=0.71 m
when he jumps to the ground, the only acceleration is acceleration due to gravity g
<u>motion1 from top to ground </u>
initial velocity u=0
we have to calculate final velocity v using the following equation of motion.

use height of the building as the distance s as the jump from top to the ground is only described here.
<u>Motion 2 on the ground</u>
v=0
u=8.3(final velocity of motion 1)
The deceleration after striking the ground can be calculated from the equation of motion

The decelerating distance is used in the place of s since since the motion after hitting the ground is described in this case.
The equation of force is

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Explanation:
Newton's second law, which states that the force F acting on a body is equal to the mass m of the body multiplied by the acceleration a of its centre of mass, F = ma, is the basic equation of motion in classical mechanics.
Answer:
Swim swim swim swim swim swim swim swim swim swim swim swim.