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asambeis [7]
3 years ago
8

A roller coaster goes from 2.00 m/s [forward] to 10.0 m/s [forward) in 4.50 s. What is its acceleration?

Physics
1 answer:
agasfer [191]3 years ago
8 0
The answer would be 1.77778:

We must use the kinematic equation v = v0 + at, then fill in the elements given and solve which equals 1.77778
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(a) 4.14 rad/s^2

The relationship beween centripetal acceleration and angular speed is

a=\omega^2 r

where

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(b) 21.3 m/s

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v=\omega r

where

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\omega=4.14 rad/s

r = 5.15 m

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v=(4.14 rad/s)(5.15 m)=21.3 m/s

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Answer:

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a=\dfrac{v^2}{d}

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So, the centripetal acceleration of the satellite is a=0.22\ m/s^2. Hence, this is the required solution.

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