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laila [671]
4 years ago
9

A 170 g air-track glider is attached to a spring. The glider is pushed in 11.2 cm against the spring, then released. A student w

ith a stopwatch finds that 14 oscillations take 11.0 s. What is the spring constant?
Physics
1 answer:
4vir4ik [10]4 years ago
7 0

Answer:k = 10.83 N/m²

Explanation: The angular frequency (ω), spring constant (k) and mass is related by the formulae below

ω = √k/m

But ω = 2πf, where f = frequency.

f = number of oscillations /time taken

Number of oscillations = 14, time taken = 11s

f = 14/11 = 1.27Hz.

ω = 2×22/7×1.27

ω = 7.98 rad/s.

By substituting this parameters into ω = √k/m

Where ω = 7.98rad/s, m = 170g = 170/1000 = 0.17kg.

7.98 = √k/0.17

By squaring both sides

(7.98)² = k/ 0.17

k = (7.98)² × 0.17

k = 10.83 N/m²

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I need help please someone !!!!! Would appreciate it
babymother [125]

Answer:

Yes, it would make it back up.

Explanation:

If it has 100,000 Joules of gravitational potential energy at the top of the hill, by the time the cart gets to the bottom, it will become PE = 0, KE = 90,000 since 10% of 100,000 is 10,000. The cart only requires 80,000J to climb back up so it should easily do so.

I didn't quite understand if the 10% energy loss is total, or every time it goes up or down, but it isn't a problem because 10% of 90,000 is 9,000, which means it would have 81,000J of energy on the way back up IF it loses energy due to friction on the way back up also.

The only physical law you need to prove this is the Law of Conservation of Energy: no energy is lost, only transformed; 10% of the energy becomes heat, the rest remains mechanical energy, which is the reason why the reasoning above works.

5 0
3 years ago
When play stops in the game of hockey, to restart the action what is that called? (Hint: there are several points on the rink)
QveST [7]

Answer:

Face - off

Explanation:

Face - off is a term used in ice hockey to start periods of play and also to restart the play/action after a previous stoppage.

This face - off involves two opposing players from the 2 opposing teams standing opposite each other at an approximate distance of one sticks blade with the game official dropping the puck between them. Thereafter, two players will then to try to gain possession of the puck.

3 0
3 years ago
I really need help !!
Marat540 [252]

Answer:

The generator will work only if the magnetic field associated with the turns of coil change.

here both magnet and coil are stationary with respect to each other so no electromagnetic induction would take place. so no indiced current will be produced.

the student has to introduce some mechanism either to rotate the coil or the magnet

5 0
4 years ago
Two metal plates 15mm apart have a potential difference of 750v between them. The force on a small charged sphere placed between
Romashka [77]

Answer:

50,000 V/m

Explanation:

The electric field between two charged metal plates is uniform.

The relationship between potential difference and electric field strength for a uniform field is given by the equation

\Delta V=Ed

where

\Delta V is the potential difference

E is the magnitude of the electric field

d is the  distance between the plates

In this problem, we have:

\Delta V=750 V is the potential difference between the plates

d = 15 mm = 0.015 m is the distance between the plates

Therefore, rearranging the equation we find the strength of the electric field:

E=\frac{\Delta V}{d}=\frac{750}{0.015}=50,000 V/m

6 0
4 years ago
Spaceship 1 and Spaceship 2 have equal masses of 300 kg. Spaceship 1 has an initial momentum magnitude of 600 kg-m/s. What is it
kati45 [8]

Answer:

Initial speed of the spaceship 1, v = 2 m/s

Explanation:

Given that :

Mass of spaceship 1 and 2 that have equal mass are 300 kg

Initial momentum of the spaceship 1 is 600 kg-m/s

To find :

We need to find the initial momentum of spaceship 1.

Solve :

The momentum of an object is equal to the product of mass and its velocity. Its SI unit is kg-m/s. Mathematically, it is given by :

p=mv

v=\dfrac{p}{m}

v=\dfrac{600\ kg-m/s}{300\ kg}

v = 2 m/s

Therefore the initial speed of spaceship 1 is 2 m/s. Hence, this is the required solution.

6 0
4 years ago
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