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2 years ago

Which of the following is equal to this expression?

Mathematics

1 answer:

Jlenok [28]2 years ago

8 0

Answer:

B) $8\sqrt[4]{4}$

Step-by-step explanation:

$(2^{8} *2^{6} )^\frac{1}{4} = (2^{8+6} )^\frac{1}{4} =(2^{14} )^\frac{1}{4} =2^{\frac{7}{2} }=\sqrt{2^{7} } =2^{3} \sqrt{2} =8\sqrt{2} = 8\sqrt[4]{2^{2} } = 8\sqrt[4]{4}$

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Step-by-step explanation:

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3 years ago

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Elis [28]

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3 years ago

fladli sells televisions. He earns a fixed amount for each television and an additional $ 20 if the buyer gets an extended warra

ivanzaharov [21]

Answer: $80

Step-by-step explanation:

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4 years ago

Help plsss

LenKa [72]

<h3></h3><h2>⭐ Development:</h2><h3></h3>

Having the expression, let's modify it so it becomes a 2nd degree equation:

$\large {\text {$ \sf \cfrac{1}{2x^2} -2 = 0 $}}$

Now, we will multiply per 2x² both sides of equation...

$\large {\text {$ \sf \cfrac{1}{2x^2}\cdot \:2x^2-2\cdot \:2x^2=0\cdot \:2x^2 $}$

$\searrow$

$\large {\text {$ \sf 1-4x^2=0$}}$

We have to write in standard form...

$\large {\text {$ \sf -4x^2+1 = 0 $}}$

<u />

$\large {\text{$\sf x=\cfrac{-b\pm\sqrt{b^2-4ac}}{2a} \quad\rightarrow\quad x=\cfrac{-0\pm\sqrt{0^2-4\cdot (-4) \cdot1} }{2\cdot (-4) } \:\rightarrow\:\: x=\cfrac{-0^2 \pm4}{2 \cdot(-4)} $}}$

$\huge {\text {$ \sf \downarrow$}}$

$\large {\text {$\sf {\bf x_1} = \cfrac{-0+4}{2\left(-4\right)}= \cfrac{-1}{2} $}}$ $\large {\text {$\sf {\bf x_2 }=\cfrac{-0-4}{2\left(-4\right)} = \cfrac{1}{2} $}}$