A study was conducted on the effects of long-term marriage (more than 10 years). Researchers gathered data from a random sample
1 answer:
You might be interested in
Answer:
Maximum Profit = 13050
when
The Toy company sells Jordan Size hoops = 7
The Toy company sells Shaq Size hoops = 3
Step-by-step explanation:
Given - The Toy Company sells two types of kids' basketball hoops, Jordan size and Shaq size. A neighborhood needs no more than 10 Jordan sizes and Shaq sizes all together. The Company requires the neighborhood to order at least 2 Jordan sizes and at least 3 Shaq sizes. The Toy Company makes a profit of $1,350 on the Jordan size and $1,200 on the Shaq size.
To find - What is the maximum profit they can make given the constraints above?
Proof -
Let us assume that,
The Toy company sells Jordan Size hoops = x
The Toy company sells Shaq Size hoops = y
Now,
Given that, A neighborhood needs no more than 10 Jordan sizes and Shaq sizes all together.
⇒x + y ≤ 10
Now,
Given that, The Company requires the neighborhood to order at least 2 Jordan sizes and at least 3 Shaq sizes.
⇒ x ≥ 2
y ≥ 3
Now,
Given that,
The Toy Company makes a profit of $1,350 on the Jordan size and $1,200 on the Shaq size.
So,
The objective function becomes
Z = 1350x + 1200 y
So,
The Linear Programming Problem (LPP) becomes
Maximize Z = 1350x + 1200 y
Subject to
x + y ≤ 10
x ≥ 2
y ≥ 3
x, y ≥ 0
We will Solve the LPP by Graphical method.
The graph is as follows :
The points on the Boundary are -
A(2, 8)
B(2, 3)
C(7, 3)
So,
Points (x,y) Objective function value ( Z = 1350x + 1200y)
B(2,3) 1350(2) + 1200(3) = 6300
C(7,3) 1350(7) + 1200(3) = 13050
A(2,8) 1350(2) + 1200(8) = 12300
So,
Maximum value = 13050 at point C(7,3)
∴ we get
Maximum Profit = 13050
when
The Toy company sells Jordan Size hoops = x = 7
The Toy company sells Shaq Size hoops = y = 3
Let
x-------> the length of the rectangle
y------> the width of the rectangle
we know that
The area of the rectangle is equal to
The area of the two congruent right triangles is equal to the area of the rectangle
so
-------> equation A
-----> equation B
Substitute equation B in equation A
--------> equation that can be used to solve for the length of the rectangle
Using a graph tool-------> solve the quadratic equation
see the attached figure
The solution is
-----> the length of the rectangle
Find the value of y
----> the width of the rectangle
Statements
<u>case A)</u> The area of the rectangle is square inches
The statement is True
See the procedure
<u>Case B)</u> The equation can be used to solve for the dimensions of the triangle
The statement is False
Because, the equation can be used to solve for the dimensions of the triangle
<u>case C)</u> The equation can be used to solve for the length of the rectangle
The statement is True
see the procedure
<u>case D)</u>The triangle has a base of inches and a height of
inches
The statement is True
Because, the base of the triangle is equal to the length of the rectangle and the height of the triangle is equal to the width of the rectangle
<u>case E)</u> The rectangle has a width of inches
The statement is False
See the procedure
Given:
Starting point = (0,0)
First ride = (0,4)
Second ride = (3,0)
In map, each unit = 100 ft
To find:
The actual distance between first and second ride.
Solution:
Distance formula: Distance between two points is
Using the distance formula, we get the distance between first ride and second ride in the map is
So, the distance between first ride and second ride in the map is 5 units.
We have,
1 units = 100 ft
5 units = 500 ft
The actual distance between first and second ride is 500 ft.
Therefore, the correct option is C.