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3 years ago

3a+4b=5a-t solve for a

2 answers:

8 0

Solution for 3A-4B+5A= equation:

Simplifying
3A + -4B + 5A = 0

Reorder the terms:
3A + 5A + -4B = 0

Combine like terms: 3A + 5A = 8A
8A + -4B = 0

Solving
8A + -4B = 0

Solving for variable 'A'.

Move all terms containing A to the left, all other terms to the right.

Add '4B' to each side of the equation.
8A + -4B + 4B = 0 + 4B

Combine like terms: -4B + 4B = 0
8A + 0 = 0 + 4B
8A = 0 + 4B
Remove the zero:
8A = 4B

Divide each side by '8'.
A = 0.5B

Simplifying
A = 0.5B

7nadin3 [17]3 years ago

5 0

Answer:

2b+t/2=a

Step-by-step explanation:

3a + 4b = 5a-t

-3a -3a

4b = 2a - t

+t +t

4b + t = 2a

/2 /2

2b+t/2=a

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garik1379 [7]

Answer:

y=64°

Step-by-step explanation:

Within a trapezoid, the angles on the same side of a leg add up to 180:

(6x+20)+(4x)=180

6x+4x=180-20

10x=160

x=16

Since the base lines are parallel, and the leg lines are equal in length, y=4x

y=4(16)

y=64°

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3 years ago

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Answer:

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4 years ago

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4 years ago

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3 years ago

Using the Law of Cosines, in triangle DEF, if e=18yd, d=10yd, f=22yd, find measurement of angle D

Ivahew [28]

Check the picture below.

$\bf \textit{Law of Cosines}\\ \quad \\
c^2 = {{ a}}^2+{{ b}}^2-(2{{ a}}{{ b}})cos(C)\implies 
c = \sqrt{{{ a}}^2+{{ b}}^2-(2{{ a}}{{ b}})cos(C)}
\\\\\\
\cfrac{{{ a}}^2+{{ b}}^2-c^2}{2{{ a}}{{ b}}}=cos(C)\implies cos^{-1}\left(\cfrac{{{ a}}^2+{{ b}}^2-c^2}{2{{ a}}{{ b}}}\right)=\measuredangle C\\\\
-------------------------------\\\\
\begin{cases}
d=10\\
e=18\\
f=22
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$\bf \implies cos^{-1}\left(0.893\overline{93}\right)=\measuredangle D\implies 26.63^o\approx \measuredangle D$

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4 years ago