1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
anygoal [31]
3 years ago
9

If: AB= 2x + 6, AC = 51, and BC=6x +5, Find BC.

Mathematics
1 answer:
Marina86 [1]3 years ago
3 0

Answer:

<h3>Assuming A, B, and C are collinear and B is between A and C then BC = 35 </h3>

Step-by-step explanation:

Assuming A, B, and C are collinear and B is beetween A and C

AB + BC  = AC

2x + 6 + 6x + 5 = 51

 8x + 11 = 51

    8x = 40

     x = 5

BC = 6x+5 = 6×5 + 5 = 35

You might be interested in
Mr.Calzada buys flags for his store.Each flag cost $28.How many flags can he buy for $350?What does the remainder represent?
Lubov Fominskaja [6]
The remainder is how much flags she needs to buy
3 0
4 years ago
Read 2 more answers
Problem
lys-0071 [83]
Eight bicycles on each rack! 24/3=8
7 0
3 years ago
Read 2 more answers
Banananana help me i need you
weeeeeb [17]
The first question should be a Pentagon as it has 5 sides, but it should also be a regular shape.
Pentagon; Regular
----------------------------
The second question shows something that obviously is not a square nor rectangle, so by process of elimination Parallelogram is your answer.
Parallelogram
8 0
4 years ago
Suppose 462 of 500 randomly selected college students said they would be embarrassed to truthfully admit they could not read at
ANEK [815]

Answer:

We conclude that there is a significant difference in the proportion of all college students who would be embarrassed by these two admissions.

Step-by-step explanation:

We are given that 462 of 500 randomly selected college students said they would be embarrassed to truthfully admit they could not read at a fourth grade level.

Further suppose 135 of 500 randomly selected college students said they would be embarrassed to truthfully admit they could not "do math" at a fourth grade level (like fractions).

<em>Let </em>p_1<em> = proportion of college students who would be embarrassed to truthfully admit they could not read at a fourth grade level.</em>

p_2<em> = proportion of college students who would be embarrassed to truthfully admit they could not "do math" at a fourth grade level.</em>

So, Null Hypothesis, H_0 : p_1-p_2 = 0  or  p_1= p_2     {means that there is not any significant difference in the proportion of all college students who would be embarrassed by these two admissions}

Alternate Hypothesis, H_A : p_1-p_2 \neq 0  or  p_1\neq p_2     {means that there is a significant difference in the proportion of all college students who would be embarrassed by these two admissions}

The test statistics that would be used here <u>Two-sample z proportion</u> <u>statistics</u>;

                       T.S. =  \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2}  } }  ~ N(0,1)

where, \hat p_1 = sample proportion of college students who would be embarrassed to admit they could not read at a fourth grade level = \frac{462}{500} = 0.924

\hat p_2 = sample proportion of college students who would be embarrassed to admit they could not "do math" at a fourth grade level = \frac{135}{500} = 0.27

n_1 = sample of college students = 500

n_2 = sample of college students = 500

So, <em><u>test statistics</u></em>  =  \frac{(0.924-0.27)-(0)}{\sqrt{\frac{0.924(1-0.924)}{500}+\frac{0.27(1-0.27)}{500}  } }

                              =  28.28

The value of z test statistics is 28.28.

<u>Also, P-value of the test statistics is given by;</u>

          P-value = P(Z > 28.28) = Less than 0.0005%

<u></u>

<u>Now, at 0.10 significance level the z table gives critical values of -1.645 and 1.645 for two-tailed test.</u>

Since our test statistics doesn't lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that there is a significant difference in the proportion of all college students who would be embarrassed by these two admissions.

5 0
4 years ago
Pats garden is shaped like a rectangle with two pair of sides of equal length, and it has a perimeter of 28 feet. Explain how to
Contact [7]
Hi Fareed134,
If you want to find the other lengths of the sides, all you have to do is take the side you know (10) and subtract it from 28. Then, divide it in half to get 2 longer sides, and divide 10 in half to get the 2 shorter sides.
28-10=18
18/2=9
10/2=5
the lengths of the other sides are 9,9,5 and 5.
Hope this helps! :)

6 0
4 years ago
Read 2 more answers
Other questions:
  • Solve 67/50 as a decimal
    12·1 answer
  • Name each angle in four ways.
    14·1 answer
  • The cosine ratio is the _____ side over the hypotenuse. adjacent opposite closest farthest
    14·2 answers
  • Help please with my "science" hw everything relates to math ugh
    15·1 answer
  • What can you say about the graph of the function below? check ALL that apply.
    7·1 answer
  • PLZ HELP WITH ALL!! Thanks.
    13·1 answer
  • Angelina spend $50 on 16 packages of cookies for her club members. sugar cookies cost $2.50 per package and chocolate chip cooki
    5·1 answer
  • Will mark Brianliest !!!!!!!!!!! Please answer correctly !!!!!
    15·1 answer
  • Sam walks from home to his school which is 0.75 miles away in 12 minutes. How fast was he walking?
    11·1 answer
  • The length and the width of a rectangle are in the ratio of 5 to 2, and the area is 1,000 sq. ft. Find the dimensions.
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!