Let's begin noting that a triangle is isosceles if and only if two of its angles are congruent. We can thus find the angle <ABP, recalling that the sum of the interior angles of a triangle is equal to 180°.
![\angle \: ABP = \frac{180 - 80}{2} = 50 \degree](https://tex.z-dn.net/?f=%20%5Cangle%20%5C%3A%20ABP%20%3D%20%20%5Cfrac%7B180%20-%2080%7D%7B2%7D%20%20%3D%2050%20%5Cdegree)
Finally, let point K be the intersection between segments BC and PQ, and let's note that the triangle PQB is a right isosceles triangle, since all the angles in a square are equal to 90°, and the two triangles APB and BQC are congruent.
Therefore, the angle BKQ is equal to 180-50-45=85°.
Of course angle BKP=180-85=95°.
Hope this helps :)
Simplified expression is 6y² - 24y - 51. Value for y=-2 is 21 and value for y=3 is -69.
Step-by-step explanation:
- Step 1: Given expression is 3y(2y-7) - 3(y - 4) - 63. Simplify it.
⇒ 6y² - 21y - 3y + 12 - 63
⇒ 6y² - 24y - 51
- Step 2: Find value of the expression for y = -2
⇒ 6y² - 24y - 51 = 6(-2)² - 24(-2) - 51 = 24 + 48 - 51 = 21
- Step 3: Find value of the expression for y = 3
⇒ ⇒ 6y² - 24y - 51 = 6(3)² - 24(3) - 51 = 54 - 72 - 51 = -69
Answer: x < -3 or x > 5
Step-by-step explanation: Interval notation shows the values of x. X is less than -3, or greater than 5.
K:A
5:3 (before)
15:9
since the total number of stamps didn't change, the total ratio should be the same.
7:5(after)
14:10
so this means 1 unit is 10stamps.
14-10=4
4 X 10= 40
Kaye have 40 more stamps than Alberto.