I think it’s 220m. Since 5 rounds are equal to 1100m then you divide by 5 to see how much he covers in one
<span>f(x)=2x
f(1)=2*1=2
f^2(1)=2*2*1=4
f^3(1) =2*2*2*1=8
1. If you
continue this pattern, what do you expect would happen to the numbers as
the number of iterations grows?
I expect the numbers continue growing multiplying each time by 2.
Check your result by conducting at
least 10 iterations.
f^4(1) = f^3(1) * f(1) = 8*2 = 16
f^(5)(1) = f^4(1) * f(1) = 16 * 2 = 32
f^6 (1) = f^5 (1) * f(1) = 32 * 2 = 64
f^7 (1) = f^6 (1) * f(1) = 64 * 2 = 128
f^8 (1) = f^7 (1) * f(1) = 128 * 2 = 256
f^9 (1) = f^8 (1) * f(1) = 256 * 2 = 512
f^10 (1) = f^9 (1) * f(1) = 512 * 2 = 1024
2. Repeat the process with an initial value of −1.
What happens as the number of iterations grows?
f(-1) = 2(-1) = - 2
f^2 (-1) = f(-1) * f(-1) = - 2 * - 2 = 4
f^3 (-1) = f^2 (-1) * f(-1) = 4 * (-2) = - 8
f^4 (-1) = f^3 (-1) * f(-1) = - 8 * (-2) = 16
f^5 (-1) = f^4 (-1) * f(-1) = 16 * (-2) = - 32
As you see the magnitude of the number increases, being multiplied by 2 each time, and the sign is aleternated, negative positive negative positive ...
</span>
Answer:14
Step-by-step explanation:
Well for the answer you just answer the opposite of the question
Answer:
B
Step-by-step explanation:
First, find the slope by using change in y divided by change in x.
Change in y = 5 - 2 = 3
Change in x = 2 - 1 = 1
This means that the slope is 3/1 = 3.
Then, you put it in the point-slope form so:
(y - 2) = 3(x - 1)
