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2 years ago

How to do this friends ???

Mathematics

1 answer:

jonny [76]2 years ago

5 0

$~~~~~~\dfrac 6{x+1} = \dfrac 5{x-3}\\\\\\\implies 6(x-3) = 5(x+1)~~~~~~~~~~~~~~~~~~~~~~~~;[\text{Cross - Multiply}] \\\\\\\implies 6x - 18 = 5x +5\\\\\\\implies 6x -5x = 5+ 18\\\\\\\implies x = 23$

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Find the area of a circle with a circumference of 12.56 units

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Answer: The area is 12.55

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3 years ago

The table shows the amount of red paint that can be added to different amounts of white paint while making a custom paint color

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3 years ago

(Giving Brainiest)<br><br>Geometry Semester 1: Triangles

LekaFEV [45]

Answer:

The answer is "Option A"

Step-by-step explanation:

The Side Angle Side postulates if the two sides, as well as the angle of a triangular, are two sides consistent as well as the angle of a separate triangle included, the two triangles are compatible.

In this situation, the triangle ABC contains two sides AC and BC, with angle C included but which corresponds with both the sides BD and BC, as well as the angle B included in the triangle BCD Added.

3 0

3 years ago

A cylindrical can without a top is made to contain 25 3 cm of liquid. What are the dimensions of the can that will minimize the

Basile [38]

Answer:

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

Step-by-step explanation:

Given that, the volume of cylindrical can with out top is 25 cm³.

Consider the height of the can be h and radius be r.

The volume of the can is V= $\pi r^2h$

According to the problem,

$\pi r^2 h=25$

$\Rightarrow h=\frac{25}{\pi r^2}$

The surface area of the base of the can is = $\pi r^2$

The metal for the bottom will cost $2.00 per cm²

The metal cost for the base is =$(2.00× $\pi r^2$ )

The lateral surface area of the can is = $2\pi rh$

The metal for the side will cost $1.25 per cm²

The metal cost for the base is =$(1.25× $2\pi rh$ )

$=\$2.5 \pi r h$

Total cost of metal is C= 2.00 $\pi r^2$ + $2.5 \pi r h$

Putting $h=\frac{25}{\pi r^2}$

$\therefore C=2\pi r^2+2.5 \pi r \times \frac{25}{\pi r^2}$

$\Rightarrow C=2\pi r^2+ \frac{62.5}{ r}$

Differentiating with respect to r

$C'=4\pi r- \frac{62.5}{ r^2}$

Again differentiating with respect to r

$C''=4\pi + \frac{125}{ r^3}$

To find the minimize cost, we set C'=0

$4\pi r- \frac{62.5}{ r^2}=0$

$\Rightarrow 4\pi r=\frac{62.5}{ r^2}$

$\Rightarrow r^3=\frac{62.5}{ 4\pi}$

⇒r=1.71

Now,

$\left C''\right|_{x=1.71}=4\pi +\frac{125}{1.71^3}>0$

When r=1.71 cm, the metal cost will be minimum.

Therefore,

$h=\frac{25}{\pi\times 1.71^2}$

⇒h=2.72 cm

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

6 0

3 years ago

Can someone please help me!

Sindrei [870]

Answer:

The Answer is x=6 2/3

Step-by-step explanation:

The Area of a triangle is A= 1/2 bh, so we should think of the triangle as half of a square/rectangle. This means the total area of the theoritical Square is 400 sq ft. We then figure out this equation:

12 * 5x = 400

400/12 = 5x

80/12 = x which is equal to 6 2/3.

Hope this helps!

5 0

4 years ago