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3 years ago

5

Math question || thank uu

1 answer:

lesya [120]3 years ago

4 0

Answer:

Step-by-step explanation:

plot an open circle on the 4 and a closed circle on the 10. Then draw a line that goes from 4 to 10.

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Solve E = mc2 for c. A) c = E m B) c = m E C) c = + m E D) c = + E m

S_A_V [24]

$C=\sqrt{E/M}$

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3 years ago

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Fifty-three percent of employees make judgements about their co-workers based on the cleanliness of their desk. You randomly sel

GarryVolchara [31]

Answer:

The unusual $X$ values for this model are: $X = 0, 1, 2, 7, 8$

Step-by-step explanation:

A binomial random variable $X$ represents the number of successes obtained in a repetition of $n$ Bernoulli-type trials with probability of success $p$ . In this particular case, $n = 8$ , and $p = 0.53$ , therefore, the model is ${8 \choose x} (0.53) ^ {x} (0.47)^{(8-x)}$ . So, you have:

$P (X = 0) = {8 \choose 0} (0.53) ^ {0} (0.47) ^ {8} = 0.0024$

$P (X = 1) = {8 \choose 1} (0.53) ^ {1} (0.47) ^ {7} = 0.0215$

$P (X = 2) = {8 \choose 2} (0.53)^2 (0.47)^6 = 0.0848$

$P (X = 3) = {8 \choose 3} (0.53) ^ {3} (0.47)^5 = 0.1912$

$P (X = 4) = {8 \choose 4} (0.53) ^ {4} (0.47)^4} = 0.2695$

$P (X = 5) = {8 \choose 5} (0.53) ^ {5} (0.47)^3 = 0.2431$

$P (X = 6) = {8 \choose 6} (0.53) ^ {6} (0.47)^2 = 0.1371$

$P (X = 7) = {8 \choose 7} (0.53) ^ {7} (0.47)^ {1} = 0.0442$

$P (X = 8) = {8 \choose 8} (0.53)^{8} (0.47)^{0} = 0.0062$

The unusual $X$ values for this model are: $X = 0, 1, 7, 8$

6 0

3 years ago

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PLEASE HELP!!!! ASAP!!!!!

SCORPION-xisa [38]

-6 5 -3 is the corrdante did those sir

8 0

3 years ago

“I am thinking of a number such that 6 less than the product of 7 and this number is 85.”

Arada [10]

let x = the number

7x - 6 =85

add 6 to each side

7x =91

divide each side by 7

x = 91 /7 = 13

Answer is B 13

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3 years ago

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Help on question 4 <br> ❤️❤️❤️

kompoz [17]

2/5, 1/10, and 1/20 are all less than 1/2

5 0

3 years ago