First you can count multiples of 7 all the way up to 84. 7,14,21,28,35,42,49,56,63,70,77,and 84.
Or you can do 7 x 12 equals 84.
Second write down the long division way 84/7.
7 goes into 8 one time write 7 at the top then write one at the bottom bring down the 4 and make it 14
you know 7 x 2 = 14 so 12 x 7 equals 14.
This is a combination problem. The approach to this is by using the nCr method, where n is the number of total objects and r is the number of success. For example, if you want to get 3 red out of the total 4, then that would be 4C3. That means,
4C3 = 4!/3!(4 - 3)! = 4 ways
If you want to get 2 green out of the total 6, then that would be 6C2. That means,
6C2 = 6!/2!(6-2)! = 15 ways
Therefore, there are a total of 4+15 = <em>19 ways</em>.
By dividing each general term by 3.
Example:
(3/3=1)
