Question

(x+26=y) and (y-12=z) if x+y+z=71 solve for x

Answer 1

Answer:

$\mathsf{x = \frac{31}{3}}$

Step-by-step explanation:

$\textsf {Given :}$

$\implies \mathsf {x + 26 = y}$

$\implies \mathsf {y - 12 = z}$

$\implies \mathsf{x + y + z = 71}$

$\textsf {Substitute for y and z in the 3rd equation :}$

$\implies \mathsf {x + x + 26 + y - 12 = 71}$

$\implies \mathsf {2x + 14 + x + 26 = 71}$

$\implies \mathsf {3x + 40 = 71}$

$\implies \mathsf {3x = 31}$

$\implies \mathsf {x = \frac{31}{3}}$