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d1i1m1o1n [39]
2 years ago
15

WHICH INEQUILITY IS EQUIVALENT TO X-4<9

Mathematics
2 answers:
frez [133]2 years ago
5 0

-------------------------------------------------------------------------------------------------------------

Answer:  \textsf{x} < \textsf{13}

-------------------------------------------------------------------------------------------------------------

Given:  \textsf{x - 4} < \textsf{9}

Find: \textsf{The simplified inequality}

Solution:  In order to simplify the inequality we can simply add 4 to both sides which would isolate x.

<u>Add 4 to both sides</u>

  • \textsf{x - 4 + 4} < \textsf{9 + 4}
  • \textsf{x} < \textsf{9 + 4}
  • \textsf{x} < \textsf{13}

Therefore, an inequality that would be equivalent to the one that was provided in the problem statement is x < 13.

densk [106]2 years ago
5 0

Answer:

x < 13

Step-by-step explanation:

We start with the given inequality:

x - 4 < 9

Now the first thing to realize is that we can add the same number to both sides of the inequality and it remains unchanged.

we add 4 to both sides of the inequality to isolate the x on the left side of the inequality.

x - 4 + 4 < 9 + 4

x < 13

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Answer:

4.54 g/cm^3

Step-by-step explanation:

d = m/v

d = 454 g ÷ 100.0 cm^3

d = 4.54 g/cm^3

3 sig figs so this answer is complete

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3 years ago
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6 0
2 years ago
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Sam complete 3 math problems in 8 minutes. How long will it take to do 15 problems?
pochemuha

Answer:

40 minutes

Step-by-step explanation:

 Math Problems                   3              15

 ----------------------                  -----     =    ------

       Minutes                          8              x

                                             3x = 15 * 8

                                               x = 15 * 8 / 3

                                               x = 120 / 3

                                               x = 40

                                                  40 Minutes

8 0
2 years ago
Suppose that 35 people are divided in a random mannerinto two teams in such a way that one team contains10 people and the other
Alisiya [41]

To be precise, the size of your sample space is <span><span>(<span>2410</span>)</span><span>(<span>2410</span>)</span></span>. This number does go on the bottom of the fraction, and what goes on top is the size of the event. Break up the event into independent events 1. choose the 2 defective bulbs, and 2. choose the remaining 8 bulbs. I don't have much choice in event 1. There is only one way to choose both of the defective balls. In other words, <span><span>(<span>22</span>)</span><span>(<span>22</span>)</span></span> (choosing 2 defective bulbs from a set of 2 defective bulbs). For event 2, there are <span><span>24−2=22</span><span>24−2=22</span></span> nondefective bulbs, and I must choose <span>88</span> of them, so that's <span><span>(<span>228</span>)</span><span>(<span>228</span>)</span></span>. Finally, since events 1 and 2 are independent, we multiply the answers for the combined event: <span><span><span>(<span>22</span>)</span><span>(<span>228</span>)</span></span><span><span>(<span>22</span>)</span><span>(<span>228</span>)</span></span></span>

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Or, since <span><span><span>(<span>22</span>)</span>=1</span><span><span>(<span>22</span>)</span>=1</span></span>,

<span><span>P=<span><span>(<span>228</span>)</span><span>(<span>2410</span>)</span></span></span><span>P=<span><span>(<span>228</span>)</span><span>(<span>2410</span>)</span></span></span></span>

Hope this helps!

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