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d1i1m1o1n [39]
2 years ago
15

WHICH INEQUILITY IS EQUIVALENT TO X-4<9

Mathematics
2 answers:
frez [133]2 years ago
5 0

-------------------------------------------------------------------------------------------------------------

Answer:  \textsf{x} < \textsf{13}

-------------------------------------------------------------------------------------------------------------

Given:  \textsf{x - 4} < \textsf{9}

Find: \textsf{The simplified inequality}

Solution:  In order to simplify the inequality we can simply add 4 to both sides which would isolate x.

<u>Add 4 to both sides</u>

  • \textsf{x - 4 + 4} < \textsf{9 + 4}
  • \textsf{x} < \textsf{9 + 4}
  • \textsf{x} < \textsf{13}

Therefore, an inequality that would be equivalent to the one that was provided in the problem statement is x < 13.

densk [106]2 years ago
5 0

Answer:

x < 13

Step-by-step explanation:

We start with the given inequality:

x - 4 < 9

Now the first thing to realize is that we can add the same number to both sides of the inequality and it remains unchanged.

we add 4 to both sides of the inequality to isolate the x on the left side of the inequality.

x - 4 + 4 < 9 + 4

x < 13

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Brut [27]

Answer:

x = 6

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
1. A box contains 10 blue Stickers, 15 red stickers , and 25 orange stickers . A sticker is selected and its color noted. Then i
denis-greek [22]

Answer:

1/25 ; 3/20 ; 3/50

Step-by-step explanation:

Total number of stickers :

(10 + 15 + 25) = 50 stickers

Probability = required outcome / Total possible outcomes

a. Selecting blue and blue stickers

P(First blue) = 10/50 = 1/5

P(second blue) = 10/50 = 1/5

1/5 * 1/5 = 1 / 25

b. Selecting one red sticker and then one orange sticker

P(First red) = 15/50 = 3/10

P(second orange) = 25/50 = 1/2

3/10 * 1/2 = 3 /20

Selecting one red sticker and then one blue sticker

P(First red) = 15/50 = 3/10

P(second blue) = 10/50 = 1/5

3/10 * 1/5 = 3 / 50

4 0
2 years ago
How does the value of log Subscript 2 Baseline 100 compare with the value of Log Subscript 6 Baseline 20?.
attashe74 [19]

You can use the change of base formula to get

\log_2(100) = \frac{\log(100)}{\log(2)} \approx 6.643856

and also

\log_6(20) = \frac{\log(20)}{\log(6)} \approx 1.671950

In general, the change of base formula is

\log_b(x) = \frac{\log(x)}{\log(b)}

8 0
2 years ago
What are the square roots of 144 over 256
stepladder [879]
Minus 12 over 16 and 12 over 16 

There you go!
8 0
3 years ago
Read 2 more answers
Can u guys help me with these two problems?? for the first one I got 76 ,but I don't think is right.
Elina [12.6K]

Answer:

See below

Step-by-step explanation:

15)

In the right-angle triangle, once one of the angles is 44º, then, the unknown angle is x.

180 = 44 + 90 + x

180 = 134 + x

x= 46

The angle y of the other triangle plus the angle x of the right-angle triangle is equal to 90º, therefore they are complementary angles.

So,

90 = x + y

90 = 46 + y

y=44

To find ?, we have

180 = 58 + 44 +?

180 = 58 + 44 +?

? =78

16)

The sum of the internal angles of the triangle with angles 50º and 25º is equal to 180º, therefore, the other angle is

180 = x + 50 + 25\\180 = x+ 75\\x=105

Once the angles are opposite, they are the same. For the triangle with the 36º angle, we have

180 = 36 + 105 + y

180 = 141+ y

y=39

?=39

3 0
2 years ago
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