I think the answer is the second one. Hope this helps!
Answer: False
Step-by-step explanation: Changing the number does affect the relationship if you switch it you might get greater than 0 or less than 0 if yo u switch them.
Hopes this helps :)
bearing in mind that standard form for a linear equation means
• all coefficients must be integers, no fractions
• only the constant on the right-hand-side
• all variables on the left-hand-side, sorted
• "x" must not have a negative coefficient
![\bf (\stackrel{x_1}{1}~,~\stackrel{y_1}{6}) ~\hspace{10em} \stackrel{slope}{m}\implies 3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{6}=\stackrel{m}{3}(x-\stackrel{x_1}{1})\implies y - 6 = 3x-3 \\\\\\ y=3x+3\implies -3x+y=3\implies \stackrel{\textit{standard form}}{3x-y=-3}](https://tex.z-dn.net/?f=%5Cbf%20%28%5Cstackrel%7Bx_1%7D%7B1%7D~%2C~%5Cstackrel%7By_1%7D%7B6%7D%29%20~%5Chspace%7B10em%7D%20%5Cstackrel%7Bslope%7D%7Bm%7D%5Cimplies%203%20%5C%5C%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%20%5Ccline%7B1-1%7D%20%5Ctextit%7Bpoint-slope%20form%7D%5C%5C%20%5Ccline%7B1-1%7D%20%5C%5C%20y-y_1%3Dm%28x-x_1%29%20%5C%5C%5C%5C%20%5Ccline%7B1-1%7D%20%5Cend%7Barray%7D%5Cimplies%20y-%5Cstackrel%7By_1%7D%7B6%7D%3D%5Cstackrel%7Bm%7D%7B3%7D%28x-%5Cstackrel%7Bx_1%7D%7B1%7D%29%5Cimplies%20y%20-%206%20%3D%203x-3%20%5C%5C%5C%5C%5C%5C%20y%3D3x%2B3%5Cimplies%20-3x%2By%3D3%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bstandard%20form%7D%7D%7B3x-y%3D-3%7D)