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2 years ago

Which of these is a correct step in constructing an angle bisector? (6

Mathematics

1 answer:

Phoenix [80]2 years ago

6 0

Answer is D, use a straightedge to draw arces which intersect at a point

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Help how many questions did you answer correctly

Lady bird [3.3K]

Answer:

450

Step-by-step explanation:

you divide 90 by 20 and times in by 100

4 0

3 years ago

Read 2 more answers

Use the Commutative Property to write an expression equivalent to -5d + 6

Ludmilka [50]

Answer:

6 - 5d is an expression equivalent to -5d + 6 using the commutative Property of Addition.

Step-by-step explanation:

Commutative Property of Addition

We know that we can add two numbers in any order.

For example,

Let 'a' and 'b' be two numbers.

We can add 'a' and 'b' numbers in any order, such as

a + b = b + a

Thus,

a + b = b + a is represented using the commutative Property of Addition.

In our case,

-5d + 6 can be written or represented using the commutative Property of Addition, such as

-5d + 6 = 6 - 5d

It is clear that -5d + 6 can be written in any order such as 6 - 5d.

In other words, 6 - 5d is an expression equivalent to -5d + 6 using the commutative Property of Addition.

Therefore, 6 - 5d is an expression equivalent to -5d + 6 using the commutative Property of Addition.

7 0

2 years ago

Sviatoslav solved the quadratic equation x^2-x-1=0 by completing the square. In the process, he came up with the equivalent equa

zimovet [89]

Answer:

$x=\frac{1+\sqrt5}{2}$ and $x=\frac{1-\sqrt5}{2}$

and b= $\frac{5}{4}$

Step-by-step explanation:

We are given that a quadratic equation

$x^2-x-1=0$

We have to solve the equation by completing square and find the value of b.

$(x)^2-2\times x\times \frac{1}{2}+(\frac{1}{2})^2-(\frac{1}{2})^2-1=0$

$(x-\frac{1}{2})^2-\frac{1}{4}-1=0$

$(x-\frac{1}{2})^2-\frac{1-4}{4}=0$

$(x-\frac{1}{2})-\frac{5}{4}=0$

$(x-\frac{1}{2})^2-(\frac{\sqrt5}{2})^2=0$

$(x-\frac{1}{2})^2=(\frac{\sqrt5}{2})^2$

$x-\frac{1}{2}=\frac{\sqrt5}{2}$ and $x-\frac{1}{2}=-\frac{\sqrt5}{2}$

$x=\frac{\sqrt5}{2}+\frac{1}{2}=\frac{1+\sqrt5}{2}$

And $x=\frac{1}{2}-\frac{\sqrt5}{2}=\frac{1-\sqrt5}{2}$

Therefore, $x=\frac{1+\sqrt5}{2}$ and $x=\frac{1-\sqrt5}{2}$

and b= $\frac{5}{4}$

6 0

3 years ago

Another brainliest help again

UkoKoshka [18]

Answer:

Im pretty sure it is 2,4, and 5

Step-by-step explanation:

3 0

3 years ago

Ana completed 40% of her homework assignment.Her assignment contains 30 math problems. How many problems does she STILL need to

Brut [27]

Answer:

your answer is 16

Step-by-step explanation:

8 0

3 years ago