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Nady [450]
2 years ago
12

What are some words that have changed meaning due to technological advances in the last 20 years?

Physics
1 answer:
vazorg [7]2 years ago
8 0

Some words that have changed meaning due to technological advances are dial, type, tweet, drone, and spam.

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If a proton is released at the equator and falls toward earth under the influence of gravity, the magnetic force on the proton w
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Positive positive side naturally because protons always move to positive side and electron always move to negative side
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for an object that is speeding up in the positive direction, what does the displacement vs. time graph look like?
slava [35]

Answer:

The speeding up is steady, it is a parabola (a=V*t+(at^2)/2), and give it's an equation in connection to time, at that point, it is conceivable to discover the separation recipe by utilizing more substantial amount mathematics(integrals).

Explanation:

7 0
3 years ago
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A cylindrical, 0.500-m rod has a diameter of 0.02 m. The rod is stretched to a length of 0.501 m by a force of 3000 N. What is t
Salsk061 [2.6K]

Answer:

Y = 4.775 x 10⁹ Pa = 4.775 GPa

Explanation:

First, we calculate the stress on the rod:

stress = \frac{Force}{Area} = \frac{3000\ N}{\pi r^2}  \\\\stress = \frac{3000\ N}{\pi (0.01\ m)^2}\\\\stress = 9.55\ x\ 10^6\ Pa = 9.55 MPa\\

Now, we calculate the strain:

strain = \frac{Change\ in Length}{Original\ Length}\\\\strain = \frac{0.501\ m - 0.5\ m}{0.5\ m}\\\\strain =  0.002\\

Now, we will calculate the Young's Modulus (Y):

Y = \frac{stress}{strain}\\\\Y = \frac{9.55\ x\ 10^6\ Pa}{0.002} \\

<u>Y = 4.775 x 10⁹ Pa = 4.775 GPa</u>

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3 years ago
Hurry help please, number 3
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Rodney is trying out one of Santa's new games that consists of three pieces that blow apart if the wrong key is inserted into th
ch4aika [34]

Answer:

<em>The third piece moves at 6.36 m/s at an angle of 65° below the horizon</em>

Explanation:

Linear Momentum

It's a physical magnitude that measures the product of the velocity by the mass of a moving object. In a system where no external forces are acting, the total momentum remains unchanged regardless of the interactions between the objects in the system.

If the velocity of an object of mass m is \vec v, the linear momentum is computed by

\displaystyle \vec{P}=m.\vec{v}

a)

The momentum of the board before the explosion is

\displaystyle \vec{P}_{t1}=m_t\ \vec{v}_o

Since the board was initially at rest

\displaystyle \vec{P}_{t1}=

After the explosion, 3 pieces are propelled in different directions and velocities, and the total momentum is

\displaystyle \vec{P}_{t2}=m_1\ \vec{v}_1\ +\ m_2\ \vec{v}_2+m_3\ \vec{v}_3

The first piece of 2 kg moves at 10 m/s in a 60° direction

\displaystyle \vec{v}_1=(10\ m/s,60^o)

We find the components of that velocity

\displaystyle \vec{v}_1=

\displaystyle \vec{v}_1=m/s

The second piece of 1.2 kg goes at 15 m/s in a 180° direction

\displaystyle \vec{v}_2=(15,180^o)

Its components are computed

\displaystyle \vec{v}_2=(15\ cos180^o,15\ sin180^o)

\displaystyle \vec{v}_2=(-15,0)\ m/s

The total momentum becomes

\displaystyle P_{t2}=2+1.2+m_3\ \vec{v}_3

Operating

\displaystyle P_{t2}=++m_3\ \vec{v}_3

Knowing the total momentum equals the initial momentum

\displaystyle P_{t2}=+m_3\ \vec{v}_3=0

Rearranging

\displaystyle m_3\ \vec{v}_3=

Calculating

\displaystyle m_3\ \vec{v}_3=

This is the momentum of the third piece

b)

From the above equation, we solve for \vec v_3:

\displaystyle \vec{v}_3=\frac{1}{3}

\displaystyle \vec{v}_3=m/s

The magnitude of the velocity is

\displaystyle \vec{v}_3|=\sqrt{2.67^2+(-5.77)^2}=6.36

And the angle is

\displaystyle tan\theta =\frac{-5.77}{2.67}=-2.161

\displaystyle \theta =-65.17^o

The third piece moves at 6.36 m/s at an angle of 65° below the horizon

5 0
3 years ago
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