Acceleration = v2 - v1 / t
a = 80 - 40 / 2
a = 40 / 2
a = 20 m/s²
In short, Your Answer would be 20 m/s²
Hope this helps!
Answer:
"Right Hand
Right Hand Rule: Magnetic fields exert forces on moving charges. This force is one of the most basic known. The direction of the magnetic force on a moving charge is perpendicular to the plane formed by v and B and follows right hand rule–1 (RHR-1) "
Explanation:
Answer:
F₃ = -151 N i + 96 N j
Explanation:
Newton's second law:
∑F = m*a Formula (1)
∑F : algebraic sum of the forces in Newton (N)
m : mass s (kg)
a : acceleration (m/s²)
Forces acting on the object
F₁= 3.0 N i + 16.0 N j
F₂ = -12.0 N i+ 8.0 N j
F₃ = F₃x N i +F₃ y N j
x component of the net force on the object
Fx=F₁x+F₂x+F₃ x
Fx = 3.0 N-12.0 N +F₃x
Fx = F₃x - 9 N
y component of the net force on the object
Fy=F₁y+F₂y+F₃ y
Fy =16.0 N+ 8.0 N +F₃y
Fy = F₃y + 24 N
Newton's second law to the object:
a = -8 m/s² i + 6.0 m/s² j
∑Fx = m*ax m=20 kg , ax = -8 m/s²
F₃x - 9 = 20 *(-8)
F₃x = -160+9
F₃x = -151 N
∑Fy = m*ay m=20 kg , ay = 6 m/s²
F₃y + 24 =20*( 6 )
F₃y =120 - 24
F₃y = 96 N
F₃ = -151 N i + 96 N j
Answer:
1) 0.51 seconds.
2) 1.45 m/s.
Explanation:
given, height from which cat falls = 1.3 m
we know that, s = ut + 
at².
here if we consider cat moment only in downward direction,
intial velocity of cat in downward direction , u = 0.
so, time, t = 
.
⇒ t = 
= 0.51 seconds.
t = 0.51 seconds.
now, consider cat moment only in forward direction
s = ut , since acceleration is zero in forward direction
⇒ u = 
.
so, u = 
= 1.45 m/s .
