Question

An engine is used to lift a beam weighing 9,800 N up to 145 m. How much work must the engine do to lift this beam? How much work must be done to lift it 290 m?

Answer 1

Explanation:

Given that,

Weight of the engine used to lift a beam, W = 9800 N

Distance, d = 145 m

Work done by the engine to lift the beam is given by :

W = F d

$W=9800\ N\times 145\ m\\\\W=1421000\ J\\\\W=1421\ kJ$

Let W' is the work must be done to lift it 290 m. It is given by :

$W'=9800\ N\times 290\ m\\\\W'=2842000\ J\\\\W'=2842\ kJ$

Hence, this is the required solution.