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const2013 [10]
3 years ago
15

An engine is used to lift a beam weighing 9,800 N up to 145 m. How much work must the engine do to lift this beam? How much work

must be done to lift it 290 m?
Physics
1 answer:
Arturiano [62]3 years ago
5 0

Explanation:

Given that,

Weight of the engine used to lift a beam, W = 9800 N

Distance, d = 145 m

Work done by the engine to lift the beam is given by :

W = F d

W=9800\ N\times 145\ m\\\\W=1421000\ J\\\\W=1421\ kJ

Let W' is the work must be done to lift it 290 m. It is given by :

W'=9800\ N\times 290\ m\\\\W'=2842000\ J\\\\W'=2842\ kJ

Hence, this is the required solution.

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A flea jumps straight up to a maximum height of 0.540 m . what is its initial velocity v0 as it leaves the ground?
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2 years ago
What mass of steam at 100°C must be mixed with 119 g of ice at its melting point, in a thermally insulated container, to produce
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Answer:M=27.92\ gm

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mass of ice m=119\ gm

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Latent heat of vaporization L_v=2256\ kJ/kg

Suppose M is the mass of steam at 100^{\circ} C

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\Rightarrow mL+mc(T_f-0)= ML_v+Mc(100-T_f)

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