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JulijaS [17]
2 years ago
9

Larry and peggy are making decisions about their bank accounts. larry wants to deposit $350 as a principle amount, with an inter

est of 4% compounded quarterly. peggy wants to deposit $350 as the principle amount, with an interest of 6% compounded monthly. explain which method results in more money after 2 years. show all work.
Mathematics
1 answer:
Kisachek [45]2 years ago
6 0

The method that results in more money after 2 years is Peggy's investment.

<h3>Which method results in more money in 2 years?</h3>

The formula for calculating the future value of an investment:

FV = P (1 + r)^nm

  • FV = Future value
  • P = Present value
  • R = interest rate
  • m = number of compounding
  • N = number of years

Future value of Larry's investment: $350 x [1 + (0.04/4)]^(4 x 2) = $379

Future value of Peggy's investment: $350 x [1 + (0.06/12)]^(12 x 2) = $394.51

To learn more about future value, please check: brainly.com/question/18760477

#SPJ1

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Because of the rainy season, the depth in a pond increases 3% each week. Before the rainy season started, the pond was 10 feet d
kari74 [83]
After first week pond will be:
10 + 10* 0.03 = 10*(1.03) feet deep
after second week it will be:

10*(1.03) + 10*(1.03)*0.03 = 10*(1.03)^2

from this we can conclude that after x week its will be:
10*(1.03)^x

Note that when second week starts our starting pond is already greater by 3%. every week we add 3% of prevous weeks size of pond

for x = 8 we get
f(x) = 10*(1.03)^8 = 12.66 or rounded 13 feet

Answer is D.

5 0
3 years ago
In 1859, 24 rabbits were released into the wild in Australia, where they had no natural predators. Their population grew exponen
Mashcka [7]

Answer:

a) P' = P

   P(t) = 24e^{0.693t} where t is step of 6 months

b) 7.7 years

c)1064.67 rabbits/year

Step-by-step explanation:

The differential equation describing the population growth is

\frac{dP}{dt} = P

Where t is the range of 6 months, or half of a year.

P(t) would have the form of

P(t) = P_0e^{kt}

where P_0 = 24 is the initial population

After 6 month (t = 1), the population is doubled to 48

P(1) = 24e^k = 48

e^k = 2

k = ln(2) = 0.693

Therefore P(t) = 24e^{0.693t}

where t is step of 6 months

b. We can solve for t to get how long it takes to get to a population of 1,000,000:

24e^{0.693t} = 1000000

e^{0.693t} = 1000000 / 24 = 41667

0.693t = ln(41667) = 10.64

t = 10.64 / 0.693 = 15.35

So it would take 15.35 * 0.5 = 7.7 years to reach 1000000

c. P' = P_0ke^{kt}

We need to resolve for k if t is in the range of 1 year. In half of a year (t = 0.5), the population is 48

24e^{0.5k) = 48

0.5k = ln2 = 0.693

k = 1.386

Therefore, P' = 1.386*24e^{1.386t}

At the mid of the 3rd year, where t = 2.5, we can calculate P'

P' = 1.386*24e^{1.386*2.5} = 1064.67 rabbits/year

4 0
3 years ago
Please give me an answer
adoni [48]
Express 0.31 as a fraction and express 0.2 as a fraction
4 0
3 years ago
Read 2 more answers
Help Pls I need the answer to t<br><br><img src="https://tex.z-dn.net/?f=0%3D-16t%5E2%2B704t" id="TexFormula1" title="0=-16t^2+7
Xelga [282]

Answer:

t=0 or t=44

Step-by-step explanation:

There are a few methods to do this, the most obvious being the use of the quadratic formula.

However, a quick check with a calculator or even your mind will reveal that 704 is divisible by 16. Thus we can solve this through factoring.

-16t(t-44)=0

Using the zero factor principle:

-16t=0 and so t=0

t-44=0 and so t=44

And thus we get the solution.

7 0
3 years ago
A bag has 2 yellow, 7 red, and 1 green marble. What is the probability of picking a red marble, replacing it, and then picking a
Ulleksa [173]
Probability red+green

first pick(red) : 7/10
2nd pick( green) : 1/10

the answer maybe like this
prob : 7/10+1/10 = 8/10 =4/5
3 0
3 years ago
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