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2 years ago

The government is the largest provider of public goods and services. give two examples of public goods and/or

Mathematics

1 answer:

nydimaria [60]2 years ago

4 0

Law enforcement and public education

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19. A $50 bottle of perfume holds 8 ounces. A $110 bottle holds 17 oz. Find the unit price for

jok3333 [9.3K]

50 divided by 8 = 6.25
1oz perfume = $6.25
110 divided by 17 = 6.4705
1oz perfume = $6.4705
Therefore the second option is cheaper

7 0

3 years ago

A 12-foot ladder leans against the wall; the base of the ladder is 2 feet away from the wall.To the nearest tenth of a foot, how

ludmilkaskok [199]

<h3>The ladder will reach a height of 11.8 feet up the wall</h3>

<em><u>Solution:</u></em>

The ladder, wall and base of the ladder from wall forms a right angled triangle

Length of ladder forms the hypotenuse

Length of ladder = 12 foot

base of the ladder from wall = 2 feet

<em><u>To find: height of wall</u></em>

By pythagoras theorem.

$c^2 = a^2+b^2$

Where,

"c" is the Length of ladder

"a" is the base of the ladder from wall

"b" is the height of wall

Substituting the values,

$12^2 = 2^2+b^2\\\\144 = 4 + b^2\\\\b^2 = 140\\\\b = \pm 11.832 \\\\Ignore\ negative\ value\\\\b \approx 11.8$

Thus, the ladder will reach a height of 11.8 feet on wall

4 0

3 years ago

What is the interquartile range of the data shown in the box plot? Please answer fast

cupoosta [38]

(First one)Low - 18
Q1 - 20
Median - 25
Q3 - 30
(Last one) High - 34

5 0

3 years ago

Any campground rides bicycles by the hour the Total cost why to rent a bicycle including deposit is presented by the function Y

alisha [4.7K]

The answer is 6+2 jaja

7 0

3 years ago

Ben consumes an energy drink that contains caffeine. After consuming the energy drink, the amount of caffeine in Ben's body decr

Airida [17]

Answer:

The 5-hour decay factor for the number of mg of caffeine in Ben's body is of 0.1469.

Step-by-step explanation:

After consuming the energy drink, the amount of caffeine in Ben's body decreases exponentially.

This means that the amount of caffeine after t hours is given by:

$A(t) = A(0)e^{-kt}$

In which A(0) is the initial amount and k is the decay rate, as a decimal.

The 10-hour decay factor for the number of mg of caffeine in Ben's body is 0.2722.

1 - 0.2722 = 0.7278, thus, $A(10) = 0.7278A(0)$ . We use this to find k.

$A(t) = A(0)e^{-kt}$

$0.7278A(0) = A(0)e^{-10k}$

$e^{-10k} = 0.7278$

$\ln{e^{-10k}} = \ln{0.7278}$

$-10k = \ln{0.7278}$

$k = -\frac{\ln{0.7278}}{10}$

$k = 0.03177289938
$

Then

$A(t) = A(0)e^{-0.03177289938t}$

What is the 5-hour growth/decay factor for the number of mg of caffeine in Ben's body?

We have to find find A(5), as a function of A(0). So

$A(5) = A(0)e^{-0.03177289938*5}$

$A(5) = 0.8531$

The decay factor is:

1 - 0.8531 = 0.1469

The 5-hour decay factor for the number of mg of caffeine in Ben's body is of 0.1469.

7 0

3 years ago