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4 years ago

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There are 220 people who voted at the 6th grade meeting.Sixty percent of the voters are in favor of changing the school mascot.H

ow many people are against changing the school mascot?

1 answer:

Amiraneli [1.4K]4 years ago

4 0

60% of 220 is 132.
220 -132 = 88

88 people.

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Answer:

There is no significant evidence to conclude that the mean waiting time is less than 3.8 minutes

Step-by-step explanation:

H0 : μ = 3.8

H1 : μ < 3.8

Test statistic :

(x - μ) ÷ s/sqrt(n)

(3.7 - 3.8) ÷ 0.6/sqrt(60)

Test statistic = - 1.29

The Pvalue from test statistic :

P(z < -1.29) = 0.0985

Reject Null if

Pvalue < α

0.0986 > 0.01 ; Hence, we fail to reject the null ;

There is no significant evidence to conclude that the mean waiting time is less than 3.8 minutes

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360/4=90

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Roduct.<br> 93 + (68 + 7)

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Step-by-step explanation:

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Does the mixed number 4 3/4 make each equation true? Choose Yes or No for each equation.

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MATH WORD PROBLEM

Sloan [31]

cost of one regular admission ticket = $ 10

cost of one senior citizen ticket = $ 5

<h3><u>Solution:</u></h3>

Let "r" be the cost of one regular admission ticket

Let "s" be the cost of one senior citizen ticket

Given that,

<em><u>On day 1 you sold 30 Regular Admission tickets and 20 Senior Citizen tickets for a total of $400</u></em>

So we can frame a equation as:

30 Regular Admission tickets x cost of one regular admission ticket + 20 Senior Citizen tickets x cost of one senior citizen ticket = $ 400

$30 \times r + 20 \times s = 400$

30r + 20s = 400 ----- eqn 1

<em><u>Day two you sell 40 Regular Admission tickets and only 10 Senior Citizen tickets for a total of $450</u></em>

So we can frame a equation as:

40 Regular Admission tickets x cost of one regular admission ticket + 10 Senior Citizen tickets x cost of one senior citizen ticket = $ 450

$40 \times r + 10 \times s = 450$

40r + 10s = 450 ---- eqn 2

<em><u>Let us solve eqn 1 and eqn 2 to find values of "r" and "s"</u></em>

Multiply eqn 2 by 2

80r + 20s = 900 --- eqn 3

Subtract eqn 1 from eqn 3

80r + 20s = 900

30r + 20s = 400

(-) ---------------------

50r = 500

<h3>r = 10</h3>

Substitute r = 10 in eqn 1

30r + 20s = 400

30(10) + 20s = 400

300 + 20s = 400

20s = 100

<h3>s = 5</h3>

<em><u>Thus we have:</u></em>

cost of one regular admission ticket = $ 10

cost of one senior citizen ticket = $ 5

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