All categories

2 years ago

How do you do linear equations

Mathematics

2 answers:

Juli2301 [7.4K]2 years ago

8 0

Answer:

Step-by-step explanation:

Step 1: Simplify each side, if needed.

Step 2: Use Add./Sub. Properties to move the variable term to one side and all other terms to the other side.

Step 3: Use Mult./Div. ...

Step 4: Check your answer.

zavuch27 [327]2 years ago

5 0

Step 1: Simplify each side, if needed.

Step 2: Use Add./Sub. Properties to move the variable term to one side and all other terms to the other side.

Step 3: Use Mult./Div. ...

Step 4: Check your answer.
I find this is the quickest and easiest way to approach linear equations.
Example 6: Solve for the variable.

You might be interested in

Write the composite function in the form f(g(x)). [Identify the inner function u = g(x) and the outer function y = f(u).] y = ta

Irina-Kira [14]

Answer:

The inner function is $u = \pi x$ .

The outer function is $f(u) = \tan{u}$ .

$\frac{dy}{dx} = y^{\prime} = \sec^{2}(u)*\pi = \pi\sec^{2}{\pi x}$

Step-by-step explanation:

The inner function is the one we apply the outer function to.

$y = \tan{\pi x}$

We apply the outer function tangent to $\pi x$ .

So, the inner function is $u = \pi x$ .

The outer function is $f(u) = \tan{u}$ .

The derivative of a compositve function

$y = f(u)$ in which $u = g(x)$ is given by the following function.

$y^{\prime} = f^{\prime}(u)*g^{\prime}(x)$

$f(u) = \tan{u}$

$f^{\prime}(u) = \sec^{2}{u}$

$u = g(x) = \pi x$

$g^{\prime}(x) = \pi$

$y^{\prime} = f^{\prime}(u)*g^{\prime}(x)$

$\frac{dy}{dx} = y^{\prime} = \sec^{2}(u)*\pi = \pi\sec^{2}{\pi x}$

7 0

2 years ago

A student factors a^6 - 64 to (a^2 - 4)(a^4 + 4a^2 + 16). Which statement about (a^2 − 4)(a^4 + 4a^2 + 16) is correct?

Lorico [155]

So that equation was definitely correct...

When you expand the equation in the bracket you'll find out that you'll get a^6 + 4a^4 + !6a^2 - 4a^4 - 16a^2 -64. then your final result will be a^6 - 64

7 0

3 years ago

Read 2 more answers

in the Sahara desert one day it was 136°F in the gobi desert a temperature of -50°F was recorded what is the difference between

Zolol [24]

Answer:

186 °F

Step-by-step explanation:

The difference is found by subtracting the smaller from the larger:

136 -(-50) = 136 +50 = 186

The difference between the two temperatures is 186 °F.

4 0

3 years ago

Does the given set of points determine a plane? Circle Yes or no

avanturin [10]

Yes it does determine a plane

4 0

3 years ago

Find the area of the following figure. 14.0 cm2 10.5 cm2 28.1cm2 17.6 cm2

Levart [38]

First option: 14.0 cm^2

Area of semicircle + area of triangle
1/2(pi)(r^2) + 1/2(b)(h)
1/2(3.14)(1.5^2) + 1/2(3)(7)
3.53+ 10.5
14.03 cm^2

7 0

2 years ago

How do you do linear equations ​

How do you do linear equations