Answer:
A) 715 ways
B) 715 ways
C) (1/715)
Step-by-step explanation:
This is a permutation and combination problem.
Since we want to select a number of people from a larger number of people, we use combination as the order of selection isn't important now.
A) How many different ways can the officers be appointed?
There are 4 officer positions.
There are 13 people in total.
We want to select 4 people from 13
Number of ways to select 4 people from 13 = ¹³C₄ = 715
B) How many different ways can the committee be appointed?
Number of committee members = 4
Total number of people available = 13
Number of ways to select 4 people from 13 = ¹³C₄ = 715
C) What is the probability of randomly selecting the committee members and getting the four youngest of the qualified candidates?
Selecting a group of the youngest candidates is just 1 amongst the total number of ways the 4 committee members can be picked,
Hence, the required probability = (1/715)
Hope this Helps!!!
![-1\ \textgreater \ [4]-5](https://tex.z-dn.net/?f=-1%5C%20%5Ctextgreater%20%5C%20%5B4%5D-5)
The right side is in fact equal to the left side so that's not the answer. For (-1, -4): ![-4\ \textgreater \ [-1]-5](https://tex.z-dn.net/?f=-4%5C%20%5Ctextgreater%20%5C%20%5B-1%5D-5)
and these are also equal. Let's try C now (-4, 1): ![1\ \textgreater \ [-4]-5](https://tex.z-dn.net/?f=1%5C%20%5Ctextgreater%20%5C%20%5B-4%5D-5)
. The absolute vale of -4 is 4 so 4 - 5 = -1 which is, in fact, less than 1. So C is our answer.