In an electroplating apparatus, where does the reduction reaction occur?

tekilochka [14]

Answer:

hydrocarbons are the answer

6 0

3 years ago

An organic (covalent) compound is determined to contain 25.54% carbon, 6.43% hydrogen, and 68.03% oxygen. The molar mass of this

aliina [53]

Answer:

https://courses.lumenlearning.com/sanjacinto-atdcoursereview-chemistry1-1/chapter/formula-mass-and-the-mole-concept/

Explanation:

https://courses.lumenlearning.com/sanjacinto-atdcoursereview-chemistry1-1/chapter/formula-mass-and-the-mole-concept/

the answer should be in there

6 0

3 years ago

An element has an average atomic mass of 1.008 amu. It consists of two isotopes , one having a mass of 1.007 amu, and one having

dimulka [17.4K]

Answer:

The most abundant isotope is 1.007 amu.

Explanation:

Given data:

Average atomic mass = 1.008 amu

Mass of first isotope = 1.007 amu

Mass of 2nd isotope = 2.014 amu

Most abundant isotope = ?

Solution:

First of all we will set the fraction for both isotopes

X for the isotopes having mass 2.014 amu

1-x for isotopes having mass 1.007 amu

The average atomic mass is 1.008 amu

we will use the following equation,

2.014x + 1.007 (1-x) = 1.008

2.014x + 1.007 - 1.007 x = 1.008

2.014x - 1.007x = 1.008 - 1.007

1.007 x = 0.001

x= 0.001/ 1.007

x= 0.0009

0.0009 × 100 = 0.09 %

0.09 % is abundance of isotope having mass 2.014 amu because we solve the fraction x.

now we will calculate the abundance of second isotope.

(1-x)

1-0.0009 = 0.9991

0.9991 × 100= 99.91%

6 0

3 years ago

The longer the bond, the smaller the bond enthalpy. the longer the bond, the smaller the bond enthalpy. false true

Temka [501]

True

As the shorter the bond, the stronger it is hence more energy will be required to overcome this bond

5 0

3 years ago

Hank's Garage has an air compressor with a holding tank that contains 200L of compressed air at 5200 torr. One day a hose ruptur

Scrat [10]

Hank's Garage has an air compressor with a holding tank that contains 200L of compressed air at 5200 torr. One day a hose ruptured and all the compressed air was released to a volume of 1370 L at atmospheric pressure.

Hank's Garage has an air compressor with a holding tank that contains a volume of 200L (V₁) of compressed air at a pressure of 5200 torr (P₁).

One day a hose ruptured and all the compressed air was released. The final pressure was the atmospheric pressure (1 atm = 760 torr) (P₂).

We can calculate the new volume (V₂) in these conditions using Boyle's law, which states there is an inverse relationship between the volume and the pressure of an ideal gas.

$P_1 \times V_1 = P_2 \times V_2\\\\V_2 = \frac{P_1 \times V_1}{P_2} = \frac{5200 torr \times 200L}{760torr} = 1370 L$

Hank's Garage has an air compressor with a holding tank that contains 200L of compressed air at 5200 torr. One day a hose ruptured and all the compressed air was released to a volume of 1370 L at atmospheric pressure.

Learn more: brainly.com/question/1437490

4 0

3 years ago