Answer : The value of
at this temperature is 66.7
Explanation : Given,
Pressure of
at equilibrium = 0.348 atm
Pressure of
at equilibrium = 0.441 atm
Pressure of
at equilibrium = 10.24 atm
The balanced equilibrium reaction is,
![PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)](https://tex.z-dn.net/?f=PCl_3%28g%29%2BCl_2%28g%29%5Crightleftharpoons%20PCl_5%28g%29)
The expression of equilibrium constant
for the reaction will be:
![K_p=\frac{(p_{PCl_5})}{(p_{PCl_3})(p_{Cl_2})}](https://tex.z-dn.net/?f=K_p%3D%5Cfrac%7B%28p_%7BPCl_5%7D%29%7D%7B%28p_%7BPCl_3%7D%29%28p_%7BCl_2%7D%29%7D)
Now put all the values in this expression, we get :
![K_p=\frac{(10.24)}{(0.348)(0.441)}](https://tex.z-dn.net/?f=K_p%3D%5Cfrac%7B%2810.24%29%7D%7B%280.348%29%280.441%29%7D)
![K_p=66.7](https://tex.z-dn.net/?f=K_p%3D66.7)
Therefore, the value of
at this temperature is 66.7
Answer:
One serving is 1/4 cup therefore 1 cup would be 4 servings. Since we have 9 cups we would then multiply 9 x 4 and the answer would be 36 servings. You have a ratio of cups to serving, so 1/4 cup : 1 serving, or .
Explanation:
The mass is 224 grams of NaOH
Answer:
The order of the reaction with respect to the gas = 2
Explanation:
Let the original gas pressure be [G₀]
Initial rate of reaction is given as
r = k [G₀]ⁿ
When 10% had reacted, amount of gas left = [0.9G₀], r = 9.71 Pa/s
r = k [0.9G₀]ⁿ = 9.71 (eqn 1)
when 20% had reacted, amount of gas left = [0.8G₀], r = 7.67 Pa/s
r = k [0.8G₀]ⁿ = 7.67 (eqn 2)
Dividing (eqn 1) by (eqn 2)
(9.71/7.67) = [0.9/0.8]ⁿ
1.266 = 1.125ⁿ
1.125ⁿ = 1.266
Take natural logarithms of both sides
n (In 1.125) = In 1.266
n = 0.236/0.118
n = 2.
Its A. the energy is stored within the nuclear of the atom