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3 years ago

The longer the bond, the smaller the bond enthalpy. the longer the bond, the smaller the bond enthalpy. false true

Chemistry

1 answer:

Temka [501]3 years ago

5 0

True

As the shorter the bond, the stronger it is hence more energy will be required to overcome this bond

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5. What is the systemic name for the following structure?

topjm [15]

Answer:

You are not showing the question, but I believe the answer is cis-3,4-dimethyl-3-hexene.

Explanation:

since the substituents are on same side, it call cis. Followed by the name.

5 0

2 years ago

In the gaseous state, chlorine exists as a diatomic molecule Cl2 (Molar mass = 70.9 g/mol). Calculate the number of moles of chl

Annette [7]

Answer:

3.67 mol Cl

Explanation:

We need to convert g of Cl 2 to moles of Cl. First we divide 130 gCl2 by the molar mass (70.90 gCl2/mol) to find out how many moles of Cl2 do we have.

130 gCl2 x $\frac{1 mol Cl2 }{70.90 gCl2}$ = 1.83 mol Cl2

Then we need to convert 1.83 mol de Cl2 to moles of Cl. We have 2 moles of Cl in every Cl2 molecule so we just need to multiply by 2.

1.83 molCl2 x $\frac{2 molCl}{1 molCl2}$ = 3.67 molCl

8 0

3 years ago

Read 2 more answers

Summarize the relationship between an electron's energy level and its location in an atom

FromTheMoon [43]

Answer:

The further an electron is from the nucleus. the greater its energy level.

Explanation:

When an electron is close to the nucleus, it is at as low an energy level as it can get.

We must put energy into an electron to pull it away from the attraction of a nucleus.

So, electrons that are further from the nucleus are at higher energy levels.

6 0

3 years ago

How many grams of material is lost in the aqueous phase if two extractions are carried out on 100 mL of a 5% (m/v) aqueous solut

san4es73 [151]

Answer:

4.94g of material

Explanation:

Partition coefficient (Kp) of a substance is defined as the ratio between concentration of organic solution and aqueous solution, that is:

Kp = 8 = Concentration in Ethyl acetate / Concentration in water

100mL of a 5% solution contains 5g of material in 100mL of water. Thus:

8 = X / 100mL / (5g-X) / 100mL

Where X is the amount of material in grams that comes to the organic phase.

8 = X / 100mL / (5g-X) / 100mL

8 = 100X / (500-100X)

4000 - 800X = 100X

4000 = 900X

4.44g = X

Thus, in the first extraction you will lost 4.44g of material from the aqueous phase.

And will remain 5g-4.44g = 0.56g.

In the second extraction:

8 = X / 100mL / (0.56g-X) / 100mL

8 = 100X / (56-100X)

448 - 800X = 100X

448 = 900X

0.50g = X

In the second extraction, you will extract 0.50g of material

Thus, after the two extraction you will lost:

4.44g + 0.50g = 4.94g of material

6 0

2 years ago

L20_UENAxleFsh-VHfg9rLfZsitva3L3UKGjmF1B299/vie Settle a dispute. X Anya claims that this challenge can be solved with a single

Fynjy0 [20]

Answer:

Neither arre correct

Explanation:

Neither Anya nor Braden are correct. This is because if you use 90 degrees, 180 degrees, or even 270 degrees you will not get the exact image, which means that the image will not be found by just a rotation because there will be a curve in the image. You can solve it if you can do 90 degree rotation and translation.

4 0

2 years ago