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Doss [256]
3 years ago
11

The longer the bond, the smaller the bond enthalpy. the longer the bond, the smaller the bond enthalpy. false true

Chemistry
1 answer:
Temka [501]3 years ago
5 0

True

As the shorter the bond, the stronger it is hence more energy will be required to overcome this bond

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cuando las particulas estan separadas una de la otra se dice que su estado de agregacion o fisico es?
Mamont248 [21]

Answer:

english:

Solid is the state in which matter maintains a certain volume and shape; liquid is the state in which matter conforms to the shape of its container, but varies only slightly in volume; gas is the state in which matter expands to fill the volume and shape of its container.

español:

Sólido es el estado en el que la materia mantiene cierto volumen y forma; el líquido es el estado en el que la materia se adapta a la forma de su recipiente, pero varía sólo ligeramente en volumen; el gas es el estado en el que la materia se expande para ocupar el volumen y la forma de su recipiente.

7 0
3 years ago
Read 2 more answers
What mass of gallium oxide, Ga₂O3, can be prepared from
Degger [83]

Answer:

(70 x 2 + 16 x 3) x 29/70 x 2 = 38,9428571 g.

Explanation:

7 0
2 years ago
What are geometric isomers?
alexandr402 [8]
Geometric isomers is defined as "each of two or more compounds that differ from each other in the arrangement of groups with respect to a double bond, ring, or other rigid structure."

I hope this answer helped you! If you have any further questions or concerns, feel free to ask! :)
7 0
3 years ago
Assume the molality of isoborneol in your product is 0.275 mol/kg. What is the melting point of your impure sample given that th
aliina [53]

Answer:

168°C is the melting point of your impure sample.

Explanation:

Melting point of pure camphor= T =179°C

Melting point of sample = T_f = ?

Depression in freezing point = \Delta T_f

Depression in freezing point  is also given by formula:

\Delta T_f=i\times K_f\times m

K_f = The freezing point depression constant

m = molality of the sample  = 0.275 mol/kg

i = van't Hoff factor

We have: K_f = 40°C kg/mol

i = 1 (  non electrolyte)

\Delta T_f=1\times 40^oC kg/mol\times 0.275 mol/kg

\Delta T_f=11^oC

\Delta T_f=T- T_f

T_f=T- \Delta T_f=179^oC-11^oC=168^oC

168°C is the melting point of your impure sample.

4 0
3 years ago
Question 5(Multiple Choice Worth 3 points)
Travka [436]

Answer: B. Stay the same

8 0
3 years ago
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